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Sedaia [141]
3 years ago
15

Math question help me

Mathematics
2 answers:
vodka [1.7K]3 years ago
8 0

may I ask if these questions' answer are always 2... or they can be other numbers too

zlopas [31]3 years ago
4 0

Answer:

A) x=2

B) x=2

C) x=3.82/3.8

B)x= -10

Step-by-step explanation:

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The integers X and Y fulfil the condition 2X=5Y. Which can be considered for X+Y?
KiRa [710]

Answer:

X + Y could equal to 1 \frac{2}{5}X or 3 \frac{1}{2}Y.

Step-by-step explanation:

2X = 5Y

Y = \frac{2}{5}X

X = \frac{5}{2}Y

Hence, X + Y could equal to X + \frac{2}{5}X = 1 \frac{2}{5}X or Y + \frac{5}{2}Y = 3 \frac{1}{2}Y.

Hence, X + Y could equal to 1 \frac{2}{5}X or 3 \frac{1}{2}Y.

6 0
3 years ago
The course for a boat race starts at point A and proceeds in the direction of S52'E for 1 hour at 8 knots to point B and then in
KATRIN_1 [288]

Answer:

20.823 nautical miles

S20°E

Step-by-step explanation:

I assume you mean ° (degrees), not ' (minutes).  There are 60 minutes in 1 degree.

S52°E means "south, 52° east", or 52° east of south.

S50°W means "south, 50° west", or 50° west of south.

1 knots = 1 nautical mile / hour, so the boat first travels 8 nautical miles from A to B, then 4.5 nautical miles from B to C, then finally back to A.

If we say A is at the origin, then the coordinates of B are:

(8 sin 52°, -8 cos 52°)

And the coordinates of C are:

(8 sin 52° − 4.5 sin 50°, -8 cos 52° − 4.5 cos 50°)

(2.857, -7.818)

So the distance from A to C is:

x = √(2.857² + (-7.818)²)

x ≈ 8.323

And the total distance of the race is:

d = 8 + 4.5 + 8.323

d = 20.823

The compass bearing from A to C is:

θ = atan(2.857 / 7.818)

θ ≈ S20°E

8 0
4 years ago
What is 57.8 minus 4.07 SIMPLIFY.
LenaWriter [7]
57.80 - 4.07

= 57.80 - 4.00 - 0.07

= 53.80 - 0.07

= 53.73
6 0
3 years ago
Read 2 more answers
Twice the sum of a number and five is equal to 40 (translate to an algebraic equation)
weeeeeb [17]
2(x + 5) = 40 ....................
8 0
3 years ago
Which algebraic expression is a polynomial with a degree of 5?
Simora [160]
First one ..............
8 0
3 years ago
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