Please answer ASAP will mark brainliest. If a reflection leaves a point unchanged, which of the following must
2 answers:
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Let t be time in hours.
Train A travels at 100 km per hour, so after t hours it will be 100t km from the station.
Train B travels at 160 km per hour, but it leaves the station one and a half hours later than train A, so its time is (t-1.5) hours. After (t-1.5) hours it will be 160(t-1.5) km from the station.
Train B will overtake train A when their distances from the station are equal.
Train B will overtake train A after 4 hours since train A left the station. It left the station at 8:00, so train B will overtake it at 12:00.
Train A travels at 100 km per hour, so after t hours it will be 100t km from the station.
Train B travels at 160 km per hour, but it leaves the station one and a half hours later than train A, so its time is (t-1.5) hours. After (t-1.5) hours it will be 160(t-1.5) km from the station.
Train B will overtake train A when their distances from the station are equal.
Train B will overtake train A after 4 hours since train A left the station. It left the station at 8:00, so train B will overtake it at 12:00.
Answer:
The common difference is 3
Step-by-step explanation:
we know that
In an <u>Arithmetic Sequence</u> the difference between one term and the next is a constant called the common difference
we have
so
therefore
The common difference is 3