ᴛʜᴇ ᴀɴsᴡᴇʀ ɪs 5.0 x 10^6
Separating the fraction into 2 fractions:
1.6 10^14
—— x ——
3.2 10^7
Dividing the numbers, and dividing the terms with the same base by subtracting their exponents:
0.5 x 10^14-7
Lastly, just subtract the exponents:
0.5 x 10^7
In scientific notation it would equivalent to:
0.5 x 10^6
Answer:
Speed of boat in still water = 64 km/hr
Speed of the current = 11 km/hr
Step-by-step explanation:
Let the speed of motorboat in still water = x km/hr
Let the speed of current = y km/hr
Motorboat travels 371 km in 7 hours going upstream.
Speed of motorboat while going upstream = speed of motorboat in still water - speed of current = (x-y)
=> ![\[x-y = \frac{371}{7}\]](https://tex.z-dn.net/?f=%5C%5Bx-y%20%3D%20%5Cfrac%7B371%7D%7B7%7D%5C%5D)
=> ![\[x-y = 53\]](https://tex.z-dn.net/?f=%5C%5Bx-y%20%3D%2053%5C%5D)
------------------------------(1)
Motorboat travels 525 km in 7 hours going downstream.
Speed of motorboat while going downstream = speed of motorboat in still water + speed of current = (x+y)
=> ![\[x+y = \frac{525}{7}\]](https://tex.z-dn.net/?f=%5C%5Bx%2By%20%3D%20%5Cfrac%7B525%7D%7B7%7D%5C%5D)
=> ![\[x+y = 75\]](https://tex.z-dn.net/?f=%5C%5Bx%2By%20%3D%2075%5C%5D)
-----------------------------(2)
Solving for x and y from (1) and (2):
Adding (1) and (2):
2x = 128
=> x = 64
Substituting the value of x in (1), y = 11
So first you do the parenthasees so 2+3=5
[5]4=20
I'm nnot sure what the _ is but I'm guessing that is is minus
and the : might mean divide so
20-15=5
{5}45/45=5
Answer:
1/2
Step-by-step explanation:
Answer:
5, 6, 7
Step-by-step explanation:
In order to solve for the three integers, we can assign a variable and set up an equation:
first integer: x
second integer: x + 1
third integer: x + 2
Given that 'the product of the first and third integer is 17 more than 3 times the second integer':
x(x + 2) = 3(x + 1) + 17
Distribute: x² + 2x = 3x + 3 + 17
Combine like terms: x² - x - 20 = 0
Factor: (x - 5)(x + 4) = 0
Set them equal to '0' and solve:
x - 5 = 0 x + 4 = 0
x = 5 x = -4
Since the problem asks for positive integers, x must equal 5:
first = 5
second = 5 + 1 = 6
third = 5 + 2 = 7
