Answer:
Students on Honor Roll had no advantage to get the Science class requested. It was a fair class assignment. In fact No Honor Roll students had advantage over honor Roll Students in obtaining Science Class as requested.
Step-by-step explanation:
Here let us streamline the information we are given one by one
1.) Honor Roll
Get Requested Science Class : 64
Did Not get Requested Science Class : 80
Total : 144
Percentage of Honor Roll Students getting Science class as requested =
= 44.44%
2.) No Honor Roll
Get Requested Science Class : 315
Did Not get Requested Science Class : 41
Total : 356
Percentage of Non Honor Roll Students getting Science class as requested 
= 88.8%
By observing the above result , we can assume that Honor Roll students did not have any advantage over non Honor Roll students in getting Science Class as they requested.
Answer:
False
Step-by-step explanation:
To find the inverse of a function, switch the variables and solve for y.
The inverse of f(n)=-(n+1)^3:
![\sqrt[3]{n} =-(y+1)](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bn%7D%20%3D-%28y%2B1%29)
![\sqrt[3]{n} =-y-1](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bn%7D%20%3D-y-1)
![\sqrt[3]{n} +1=-y](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bn%7D%20%2B1%3D-y)
![-(\sqrt[3]{n} +1)=y](https://tex.z-dn.net/?f=-%28%5Csqrt%5B3%5D%7Bn%7D%20%2B1%29%3Dy)
![-\sqrt[3]{n} -1=y](https://tex.z-dn.net/?f=-%5Csqrt%5B3%5D%7Bn%7D%20-1%3Dy)
Answer:
A) 2k+4
Step-by-step explanation:
To solve for terms of x, we need to. she sure that x is on its own side while every other term is on the other side.
To start, we will cross multiply. If we have a/b=c/d, then ad=bc
We can perform the same calculation here,
6/x=3/(k+2)
6(k+2)=3x
Divide both sides by 3
2(k+2)=x
x=2k+4
Answer:
n = -7
Step-by-step explanation:
-15= n-8
n-8=-15
+8 +8
n=-7
X^2-22x-48=0
x^2-24x+2x-48=0
x(x-24)+2(x-24)
(x+2)(x-24)
Solve by grouping if you are able to find distinct factors that multiply to the last term and add to the middle term...this method is rather easy with easy to manage numbers. Complete the square if you cannot find distinct factors that multiply to the last term and add to the middle term. Completing the square helps when the equation is in the form of a parabola.
