Answer:
The answer is B.
Step-by-step explanation:
You have to use Pythogorean Theorem, c² = a² + b² where c is the hypotenuse and a,b is the side lengths :
Let a = 40,
Let b = 9,
*Take note, hypotenuse will <u>a</u><u>l</u><u>w</u><u>a</u><u>y</u><u>s</u><u> </u><u>b</u><u>e</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>l</u><u>o</u><u>n</u><u>g</u><u>e</u><u>s</u><u>t</u><u> </u><u>l</u><u>e</u><u>n</u><u>g</u><u>t</u><u>h</u> among the 3 lengths.
*Pythogorean Theorem can only applied in a right-angle triangle.
The circle with center O has two chords AC and EF which are of same length 9.07.
OD and OB are the two perpendiculars drawn from the center O to the two chords AC and EF .It represents the distance of the chords from the centre.
The circle theorem states: congruent chords are equidistant from the center.
OD is congruent to OB.
Option A is the right answer.
Given:
Length = x + x + 3 = 2x + 3
Width = 2 + x
Area = length * width
91 ft² = (2x + 3) (2+x)
91 = 4x + 2x² + 6 + 3x
0 = 2x² + 7x + 6 - 91
0 = 2x² + 7x - 85
(2x + 17) ( x - 5)
x = -17/2 or x = 5
Let x = 5 ;
length = 2x + 3 = 2(5) + 3 = 13
width = 2 + x = 2 + 5 = 7
Area = 13 x 7 = 91
Perimeter = 2(length + width)
Perimeter = 2(13 + 7)
Perimeter = 2(20)
Perimeter = 20 feet of fencing
