The best way to answer this would be making a graph
For 1 sign it costs 54.50 and he makes 15
For 2 signs it costs 59 and he makes 30
For 3 signs it costs 63.50 and he makes 45
For 4 signs it costs 68 and he makes 60
For 5 signs it costs 72.50 and he makes 75
This means that after 5 signs Larry will be making profit
Answer:
Option (1)
Step-by-step explanation:
Given equation is,

To determine the solution of the equation we will substitute the values of 'x' given in the options,
Option (1)
For x = -0.75

0.59 = 1 - 0.44
0.59 = 0.56
Since, values on both the sides are approximately same.
Therefore, x = -0.75 will be the answer.
Option (2)
For x = -1.25

0.42 = 1 - 0.25
0.42 = 0.75
Which is not true.
Therefore, x = -1.25 is not the answer.
Option (3)
For x = 0.75

1.68 = 1 - 2.28
1.68 = -1.28
Which is not true.
Therefore, x = 0.75 is not the answer.
Option (4)
For x = 1.25

2.38 = 1 - 3.95
2.38 = -2.95
It's not true.
Therefore, x = 1.25 is not the answer.
Driving with a dog cause you just have to mixed them to ether that’s it
He can give at most 2 adult haircuts with the remaining time
<h3>How many adult haircuts at most can he give with the remaining time? </h3>
The inequality is given as:
0.75C + 1.25A <= 7
Also, we have
C = 5
Substitute C = 5 in 0.75C + 1.25A <= 7
0.75 * 5 + 1.25A <= 7
Evaluate the product
3.75 + 1.25A <= 7
Evaluate the like terms
1.25A <= 3.25
Divide by 1.25
A <= 2.6
Rewrite as
A < 3
Hence, he can give at most 2 adult haircuts with the remaining time
Read more about inequalities at:
brainly.com/question/15010638
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<u>Complete question</u>
Horace is a professional hair stylist. Let C represent the number of child haircuts and A represent the number of adult haircuts that Horace can give within 7 hours. 0.75C + 1.25A <= 7
Horace gave 5 child haircuts.
How many adult haircuts at most can he give with the remaining time?
Answer:
The answer is a Whole number which would be 7.
Step-by-step explanation:
If he need one pound of cheese for each pizza and he has seven pounds of cheese then he would be able to make 7 pizzas.