What is the solution to this system of equations?

Mathematics

1 answer:

kotykmax [81]3 years ago

6 0

Answer:

Step-by-step explanation:

There's no solution because they are not touching each other. If they intersected at one point there would b one solution and if one is exactly on top of another there's infinity solutions which looks like only one line.

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The table below gives data from a linear function. find a formula for the function.

baherus [9]

Given the following table that gives data from a linear function:

$\begin {tabular}
{|c|c|c|c|}
Temperature, $y = f(x)$ (^\circ C)&0&5&20 \\ [1ex]
Temperature, $x$ (^\circ F)&32&41&68 \\ 
\end {tabular}$

The formular for the function can be obtained by choosing two points from the table and using the formular for the equation of a straight line.

Recall that the equation of a straight line is given by
$\frac{y-y_1}{x-x_1} = \frac{y_2-y_1}{x_2-x_1}$

Using the points (32, 0) and (41, 5), we have:
$\frac{y-0}{x-32} = \frac{5-0}{41-32}= \frac{5}{9} \\ \\ \Rightarrow y=\frac{5}{9}(x-32)$

4 0

3 years ago

If it takes 10 seconds for 10 printers to print out 10 pages of paper, how many seconds will it take 50 printers to print out 50

Fed [463]

Lets use the formula $RWT=J$ to solve this, where,

R is the rate
W is the number of workers/things
T is time
J is number of jobs/things

"If it takes 10 seconds for 10 printers to print out 10 pages of paper" - here -

W is 10 printers, T is 10 seconds, and J is 10 pages. We can write:

$R(10)(10)=10\\R(100)=10\\R=\frac{10}{100}\\R=0.1$

"how many seconds will it take 50 printers to print out 50 pages of paper" - here we use $R=0.1$ (previously found) to figure out T.

$RWT=J\\(0.1)(50)T=50\\5T=50\\T=\frac{50}{5}\\T=10$

So it will take 10 seconds for 50 printers to print 50 pages.

ANSWER: 10 seconds

4 0

3 years ago

Read 2 more answers

Write these in standard form :

kotegsom [21]

$8.23\cdot10^6=8.23\cdot1,000,000=8,230,000\\\\2.4\cdot10^5=2.4\cdot100,000=240,000$

$\text{The scientific notation:}\ a\cdot10^n\ (1\leq a < 10,\ n\in\mathbb{Z})\\\\4\underbrace{50000}_{\leftarrow5}=4.5\cdot10^5\\\\320=3.2\cdot100=3.2\cdot10^2\\\\0.\underbrace{0000006}_{7\rightarrow}73=6.73\cdot10^{-7}\\\\3\underbrace{2100000}_{\leftarrow7}=3.12\cdot10^7$