Answer:
B)law of detachment
Step-by-step explanation:
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We have been given a quadratic function 
and we need to restrict the domain such that it becomes a one to one function.
We know that vertex of this quadratic function occurs at (5,2).
Further, we know that range of this function is 
.
If we restrict the domain of this function to either ![(-\infty,5]](https://tex.z-dn.net/?f=%28-%5Cinfty%2C5%5D)
or 
, it will become one to one function.
Let us know find its inverse.
Upon interchanging x and y, we get:
Let us now solve this function for y.
Hence, the inverse function would be 
if we restrict the domain of original function to and the inverse function would be 
if we restrict the domain to .
Vertical angles are congruent...they are equal....so set them equal to each other and solve for x
6x - 22 = 4x + 2
6x - 4x = 2 + 22
2x = 24
x = 24/2
x = 12 <==
Answer:
C
Step-by-step explanation:
Don't worry about the volume to start with. Just look at the area of the top or bottom.
The hole has a 4 inch diameter
d = 4
r = d/2
r = 2
Area = pi r^2
Area = pi * 2^2
Area = 4 pi
Now find the area of the top (or bottom) if the circle was not there.
L = 8
W = 6
Area = L * W
Area = 8 * 6
Area = 48
Now take away the area of the circle.
Area Top = 48 - 4 * pi
Area Top = 48 - 12.56
Area Top = 35.44
Finally, Find the volume
Volume = area of the top * height
Volume = 35.44 * 15
Volume = 531.6
Answer: Attached.
Step-by-step explanation:
Either solve the equations directly, or graph them and look for the point of intersection.
