Question

HELP FAST PLS!!!!!!!!!(will give 50 points to who answers correctly oh and dont answer fake answers i typed soo hard to do this)

Answer 1

Answer:

Step-by-step explanation:

1.A

2.C

1.C

2.A

1.B

2.21.45

3.A

I tried my best

Answer 2

Answer:

Part A Question #1) Model B Question #2 A) Model A

Part B Question #1 B) Model B uses the smallest liner Question #2 C) Model C uses the largest liner

Part C Question #1 C, Question #2 576.2 ft², A. Question #3 Correct

Part D Question #1 72.8 yd² Question #2 109.38 yd²Question #3 A. Triangular Prism

Step-by-step explanation:

Part A

Question #1

The pool as a matter of fact is a parallelepiped, a rectangular prism. And a Rectangular Prism has its Volume

Model A: 18ft x 9 3/4 and 4 1/2 The Volume is given by this formula:

Volume=w*l*d

$V_{A}=19*9 \frac{3}{4}*4 \frac{1}{2}} =833.62ft^{3} \\ V_{B} =16*10*5=800ft^{3} \\ V_{C} =15*12*4 \frac{1}{2} =810ft^{3}$

Model B needs the smallest amount of water. So Model B

Question #2

Model A needs the largest amount of water to be filled. 833.62 ft³

Part B

The pool liner area is equivalent to a rectangular area. The surface of Pool $L_{A}= 18*9 \frac{3}{4} =175.5 ft^{2} \\ L_{B}= 16*10 =160ft^{2} \\ L_{C}= 15*12=180ft^{2}$

Question #1

Model B uses the smallest liner

Question #2

Model C uses the largest liner

Part C

Question #1

C A square pyramid is made up of Four congruent triangular faces, since the base is a square.

Question #2

This question asks us how many square feet, of a red tin roof. In other words, what's the area of this red pyramid? So

Since the base of this pyramid is not going to be taken into account. Let's calculate it:

4 * Area of the Triangle, each of its base edge is also the base edge of its triangular face. Base=21.5 ft Height=13.4 ft. There are four triangular faces.

Area of the Triangle = 1/2*b*h

4* (21.5*13.4)/2= 576.2 ft²

Part D

Question #1

This huge prism has 2 equilateral triangles and 3 rectangles. The question asks us the area of the roof: 2 rectangles:

2 (6.5*5.6)=72.8 yd²

Question #2

What is the outside surface area of this house? The outside surface is given by the sum of the areas of 2 equilateral triangles+ roof

Area of an Equilateral Angle:

$A=\frac{l^{2}\sqrt{3}}{4}$

So $(\frac{6.5^{2}\sqrt{3}}{4})*2=36.58$

36.58+72.8 (previous question) =109.38 yd²

Question #3

This A-frame house is in the shape of a:  A. Triangular Prism