(4-4x)(x-3)
4x-12-(4x^2)+12x
(-4x^2)+16x-12=(pxq)(x)
The problem is modelled in the first picture shown below
To work out the resultant vector, we modelled the vectors 150N and 75N as triangle AOB is shown in the second picture with AB as the resultant vector.
We use the cosine rule to work out the length AB




(nearest whole number)
The third picture shows the full diagram of the vectors
To work out the direction of the resultant vector, we use the sin rule to find the size of angle A and angle B
Angle A






(rounded to nearest whole number)
Angle B

Direction is 60° toward negative x-axis
Answer: Magnitude 130N and direction 60° toward negative x-axis
Answer:
See below
Step-by-step explanation:
<h3>Part A</h3>
<h3>Part B</h3>
It has only one solution when the line mx + 1 is parallel to one part of |2x - 4|.
As per graph, we see m = 2 makes it parallel to y = 2x - 4. This is the only solution.
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Now, as I understand, you are looking for 2 solutions instead of one. It means the line mx + 1 will have 2 points of intersection with the line |2x - 4|.
One of those solutions is attached as well, where m = 1. And you may get many more options for this.
Answer:
it's the last one, and the missing number is 70 (the P)