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Viefleur [7K]
3 years ago
15

How are work and power shown when you are driving a car?

Physics
1 answer:
Ivanshal [37]3 years ago
8 0

When driving a car, as you very well know, the engine is working, by enabling the car to move, and helping the tires roll. Power is used by enabling the car to turn on, the engine helps again.

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An object of mass 82kg is accelerated upward at 3.2m/s/s. what force is required
vampirchik [111]

F = m · a

In order to accelerate 82 kg upward at the rate of 3.2 m/s², a NET upward force of (82kg · 3.2m/s²) =  262.4 Newtons is required.

But if the object is on or near the surface of the Earth, then there's a downward force of (82kg · 9.8m/s²) = 803.6 N already acting on it because of gravity.

So you need to apply (803.6N + 262.4N) = <em>1,066 Newtons UPward</em>, in order to cancel its own weight and accelerate it upward at that rate.  

6 0
4 years ago
What is the average power consumption in watts of an appliance that uses 5.00 KW.h of energy per day?
abruzzese [7]
(A) power = 0.208 kW = 208 watts
(B) energy = 6.6 x 10^{9} joules

Explanation:
energy consumed per day = 5 kWh
(a) find the power consumed in a day
1 day = 24 hours
power = \frac{energy}{time}
power = \frac{5}{24}
power = 0.208 kW = 208 watts

(b) find the energy consumed in a year
assuming it is not a leap year and number of days = 365 days
1 year = 365 x 24 x 60 x 60 = 31,536,000 seconds
energy = power x time
energy = 208 x 31,536,000
energy = 6.6 x 10^{9} joules
3 0
3 years ago
Who was the first man to walk on the moon?
Andrej [43]
The first person is Neil Armstrong
8 0
4 years ago
a girl pushes a cart to the left a 100-N force. a boy pushes it to the right with a 50-N force. The net force exerted on the car
AURORKA [14]
Since the net force is the amount of force favoring the side with the most force acted upon it,

100 - 50 = 50

50N to the left

Hope this helps!
5 0
4 years ago
Find the mass of the solid cylinder Dequals​{(r,theta​,z): 0less than or equalsrless than or equals2​, 0less than or equalszless
anygoal [31]

The mass of the cylinder <em>D</em> is obtained by integrating the density function over <em>D</em>:

\displaystyle\iiint_D\rho(r,\theta\,z)\,\mathrm dV

With \rho(r,\theta,z)=1+\frac z2, and

D=\left\{(r,\theta,z)\mid 0\le r\le2,0\le z\le10\right\}

the mass would be

\displaystyle\int_0^{2\pi}\int_0^2\int_0^{10}1+\frac z2\,\mathrm dz\,\mathrm dr\,\mathrm d\theta=4\pi\int_0^{10}1+\frac z2\,\mathrm dz

4\pi\left(z+\dfrac{z^2}4\right)\bigg|_0^{10}

=4\pi\left(10+\dfrac{100}4\right)=\boxed{140\pi}

6 0
3 years ago
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