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salantis [7]
3 years ago
9

19/23 Marks

Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
4 0

Answer:

0.28

Step-by-step explanation:

Let p be the probability of pasta.

Total probability is = 1

Therefore,

0.3 + 0.42 + p = 1

0.72 + p = 1

p = 1 - 0.72

p = 0.28

The probability that it will be pasta is 0.28

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guapka [62]

Answer:

1) $53.50

2)$85.10

3) $57.60

4)1.5

4) $2511.25

Step-by-step explanation:

for 1,2,3,5 take the original amount and the percentages to set up something like this

$50X1.07

which gives you the entire answer in a simple step

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3 years ago
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21 less than a number, multiplied by 4, results in 108.Find the value of the unknown number.
Anni [7]

21 - 4x = 108

<em><u>Subtract 21 from both sides</u></em>

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<em><u>Divide both sides by -4</u></em>

x = -21.75

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3 years ago
What is the fraction of 00.1
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00.1

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The time taken to deliver a pizza has a uniform probability distribution from 20 minutes to 60 minutes. What is the probability
Whitepunk [10]

Answer:

(1) The probability that the time to deliver a pizza is at least 32 minutes is 0.70.

(2a) The percentage of results more than 45 is 79.67%.

(2b) The percentage of results less than 85 is 91.77%.

(2c) The percentage of results are between 75 and 90 is 15.58%.

(2d) The percentage of results outside the healthy range 20 to 100 is 2.64%.

Step-by-step explanation:

(1)

Let <em>Y</em> = the time taken to deliver a pizza.

The random variable <em>Y</em> follows a Uniform distribution, U (20, 60).

The probability distribution function of a Uniform distribution is:

f(x)=\left \{ {{\frac{1}{b-a};\ x\in [a, b] } \atop {0};\ otherwise} \right.

Compute the probability that the time to deliver a pizza is at least 32 minutes as follows:

P(Y\geq 32)=\int\limits^{60}_{32} {\frac{1}{b-a} } \, dx \\=\frac{1}{60-20} \int\limits^{60}_{32} {1 } \, dx\\=\frac{1}{40}\times[x]^{60}_{32}\\=\frac{1}{40}\times[60-32]\\=0.70

Thus, the probability that the time to deliver a pizza is at least 32 minutes is 0.70.

(2)

Let <em>X</em> = results of a certain blood test.

It is provided that the random variable <em>X</em> follows a Normal distribution with parameters \mu = 60 and s = 18.

The probabilities of a Normal distribution are computed by converting the raw scores to <em>z</em>-scores.

The <em>z</em>-scores follows a Standard normal distribution, N (0, 1).

(a)

Compute the probability that the results are more than 45 as follows:

P(X>45)=P(\frac{X-\mu}{\sigma}> \frac{45-60}{18})=P(Z>-0.833)=P(Z

The percentage of results more than 45 is: 0.7967\times100=79.67\%

Thus, the percentage of results more than 45 is 79.67%.

(b)

Compute the probability that the results are less than 85 as follows:

P(X

The percentage of results less than 85 is: 0.9177\times100=91.77\%

Thus, the percentage of results less than 85 is 91.77%.

(c)

Compute the probability that the results are between 75 and 90 as follows:

P(75

The percentage of results are between 75 and 90 is: 0.1558\times100=15.58\%

Thus, the percentage of results are between 75 and 90 is 15.58%.

(d)

Compute the probability that the results are between 20 and 100 as follows:

P(20

Then the probability that the results outside the range 20 to 100 is: 1-0.9736=0.0264.

The percentage of results outside the range 20 to 100 is: 0.0264\times100=2.64\%

Thus, the percentage of results outside the healthy range 20 to 100 is 2.64%.

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3 years ago
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