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katen-ka-za [31]
3 years ago
10

In any engineering design problem, the first step is to understand the problem and identify one or more possible solutions. In t

his task, you’ll analyze the problems you face as the chemical engineer challenged with setting up the ammonia-making process. Recall the chemical equation for producing ammonia:
N2 + 3H2 ⇌ 2NH3 + energy

1.Explain the problem surrounding the ammonia-making process in terms of chemical equilibrium.
Chemistry
1 answer:
hichkok12 [17]3 years ago
6 0

Answer:

Explanation:

About 2,070 results (0.60 seconds)  

Answer is: at lower temperatures the reaction rate would decrease. The lower is the temperature, the slower the reaction becomes. ... Because this is exothermic reaction (enthalpy is less than zero), at lower temperatures, the equilibrium is in favor of ammonia, but the reaction doesn't proceed at a detectable rate.

Hi,

let us go through the question again

N2 + 3H2 ⇌ 2NH3 + energy  

Explain the problem surrounding the ammonia-making process in terms of chemical equilibrium.

So I would approach this question on the basis of effect of each of the reactants and products concentration on the equilibrium synthesis of ammonia.

If the concentration of any reactant is increased, the yield of ammonia is increased.

If the concentration of ammonia is reduced by removing it as it forms, the yield will as well be increased.

This reaction also yields heat meaning it is an exothermic reaction, so when we increase the temperature, the yield will be reduced. Hence it is favored by low temperature.

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Each day one astronaut exhales about 448 L of carbon dioxide. how many grams of LiOH is needed to remvoe this much carboon dioxi
Romashka [77]

Answer:

How to determine the mole of LiOH required to react with 20 moles of CO₂ per day

CO₂ + 2LiOH —> Li₂CO₃ + H₂O

From the balanced equation above,

1 mole of CO₂  required 2 moles of LiOH.

Therefore,

20 moles of CO₂ will require = 20 × 2 = 40 moles of LiOH

How to determine the mole of LiOH required by two astronauts for 3 days

Mole of LiOH for 1 person per day = 40 moles

Mole of LiOH for 2 persons per day = 2 × 40 = 80 moles

Mole of LiOH for 2 persons for 3 days = 80 × 3 = 240 moles

Explanation:

mark brainliest

7 0
2 years ago
Q8. The titration of 15.00 mL of HBr solution of unknown concentration requires 18.44 mL of a 0.100 M KOH solution to reach the
lara [203]

Answer: 0.123 M

Explanation:

According to the neutralization law:

n_1M_1V_1=n_2M_2V_2

where,

M_1 = molarity of HBr solution = ?

V_1 = volume of HBr solution = 15.00 ml

M_2 = molarity of KOH solution = 0.100 M

V_2 = volume of KOH solution = 18.44 ml

n_1 = valency of HBr = 1

n_2 = valency of KOH = 1

1\times M_1\times 15.00=1\times 0.100\times 18.44

M_1=0.123

Therefore, the concentration of the unknown HBr solution is 0.123 M

8 0
3 years ago
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