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OlgaM077 [116]
3 years ago
5

Calculate the pH of the following?

Chemistry
1 answer:
Gwar [14]3 years ago
4 0
The correct answer is c
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6.75 L of carbon dioxide gas are stored at a pressure of 175 atm. If the temperature and number of gas particles do not change,
I am Lyosha [343]

Answer:

4.24 L

Explanation:

  • 6.75 L - 175 atm

x. - 110 atm

  • <u>175atm </u><u>x</u>=<u>742.5L /atm</u>

175atm 175atm

  • therefore x=4.24 L
3 0
3 years ago
Are the chemical reactions that take place when a battery connected endothermic or exothermic
Vilka [71]

Answer:

The answer is endothermic as the heat flows into the system from the surroundings. The products are at higher energy than the reactants, as they have absorbed energy.

8 0
3 years ago
What is the answer helpnme plz
kykrilka [37]
MgH2 + 2 H2O → Mg(OH)2 + 2 H2
8 0
2 years ago
What is the volume of 2 mol of chlorine gas at STP?<br> 2.0 L<br> 11.2 L<br> 22.4 L<br> 44.8 L
nirvana33 [79]

Answer:

44.8 L

Explanation:

Using the ideal gas law equation:

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

n = number of moles (mol)

R = gas law constant (0.0821 Latm/molK)

T = temperature (K)

At Standard temperature and pressure (STP);

P = 1 atm

T = 273K

Hence, when n = 2moles, the volume of the gas is:

Using PV = nRT

1 × V = 2 × 0.0821 × 273

V = 44.83

V = 44.8 L

7 0
2 years ago
Oxygen gas can be prepared by heating potassium chlorate according to the following equation: 2KClO3(s)2KCl(s) + 3O2(g) The prod
Ipatiy [6.2K]

Answer:

The number of moles of KClO₃ reacted was 0,15 mol

Explanation:

For the reaction:

2KClO₃(s) → 2KCl(s) + 2O₂(g)

The only gas product is O₂.

Total pressure is the sum of vapor pressure of water with O₂ gas formed. Thus, pressure of O₂ is:

749mmHg - 23,8mmHg = 725,2mmHg

Using gas law:

PV/RT = n

Where:

P is pressure (725,2mmHg ≡ <em>0,9542atm</em>)

V is volume (<em>5,76L</em>)

R is gas constant (<em>0,082 atmL/molK</em>)

And T is temperature (25°C ≡ <em>298,15K</em>)

Replacing, number of moles of O₂ are <em>0,2248 moles</em>

As 2 moles of KClO₃ react with 3 moles of O₂ the moles of KClO₃ that reacted was:

0,2248 mol O₂×\frac{2 mol KClO_{3}}{3 mol O_{2}} = <em>0,15 mol of KClO₃</em>

I hope it helps!

8 0
3 years ago
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