Given:
3:15 pm - start of first showing.
30 minutes break;
20 minutes late - 2nd showing.
4:50 - start of second showing.
4:50 - 0:20 = 4:30 should be the start of the second showing.
4:00 - 4:30 = 1/2 hour break
3:15 - 4:00 = duration of the 1st showing. 45 minutes in all.
4:50 + 0:45 = 5:35 pm end of the 2nd showing.
Yes, the 2nd showing will be over by 6:30 pm.
x < 22.5; Samuel has less than 22.5 minutes to finish the race in the estimated time.
<h3>What amount of time Samuel left for the race?</h3>
The given inequality is-
From here, we define the variable x.
x = Number of the minutes left for the race
From here we can find the value of x
We have then:
Hence, Samuel has less than 22.5 minutes to finish the race in the estimated time.
To know more about inequality follow
brainly.com/question/24372553
Answer:
9
Step-by-step explanation:
step 1: 18÷2=9
step 2: answer is 9
TQRS is an inscribed quadrilateral.
5 x - 52° + 3 x + 40° = 180°
8 x - 12° = 180°
8 x = 180° + 12°
8 x = 192°
x = 192° : 8 = 24°
m∠ R = 3 · 24° + 40° = 112°
m∠ T = 5 · 24° - 52° = 68°
m∠ S = 360° - ( 68° + 68° + 112° ) = 112°
Answer:
m∠R, m∠S, m∠T = 112°, 112°, 68°.