Answer:
Step-by-step explanation:
It is given that, 
We need to find the value of 
As 
Solving LHS

Now comparing the coefficients of 
In LHS the coefficient of
is 25
In RHS the coefficient of
is 
It implies that, 
So, the value of
is 25.
Answer:
12
Step-by-step explanation:
Answer:
E
Step-by-step explanation:
The problem says that triangle BDC lies in the plane k, which means that whatever angle is formed by another point beyond this plane with any of the three segments that form BDC (BD, DC, and BC) is the same as the angle formed by the line connecting the point and the plane.
Here, we're given that AD⊥DC, which means AD forms a 90° angle with DC. Then, since DC is already on the plane, we already know for sure that AD is definitely perpendicular to plane k.
Thus, the answer is E (none of these).
It is 19 because of the Pythagorean theorem which states a squared plus b squared is c squared.
Answer:
6.5
Step-by-step explanation:
5.1+7.9=13
13 divided by 2
= 6.5