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Mathematics

1 answer:

allsm [11]3 years ago

5 0

Use photo math , I’m sure it will help

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Solve for x.<br> Sqrt8 (Sqrt2 - x) = 11

Alexus [3.1K]

Answer: $\frac{-7\sqrt{2} }{4}$

Step-by-step explanation:

So first, let's get rid of the parentheses. We can multiply it out to get $\sqrt{16}-x\sqrt{8} =11$ . We know that the square root of 16 is ±4, so now our equation is ±4 - $x\sqrt{8}$ =11. I'm guessing since the problem only has one solution it's most likely only positive 4, so let's revise our equation to 4 - $x\sqrt{8}$ =11. We can use inverse operations to make the a little easier to solve: -7= $x\sqrt{8}$ . We divide both sides by $\sqrt{8}$ to get $\frac{-7}{\sqrt{8} } =x$ , which we can rationalize (remove the square root from the denominator so that it's a proper answer) by multiplying by $\frac{\sqrt{8} }{\sqrt{8} }$ (which is equal to one so we can use it) which is equal to $\frac{-7\sqrt{8} }{8}$ . Let's finish this by simplifying it. $\sqrt{8} =2\sqrt{2}$ (2x $2^{2}$ ). We can simplify it further by simplifying the 2, making it $\frac{-7\sqrt{2} }{4}$ .

Hope this wasn't too confusing! I'll answer any questions.

8 0

3 years ago

Read 2 more answers

How do you solve for what is a? Please answer quickly?<br><br> 4(a-2)=3(a+4)

Lunna [17]

4(a-2)=3(a+4)
4a-8=3a+12
a=20

8 0

3 years ago

Si el largo de un rectángulo mide el doble del ancho que es "a", ¿cuál es su área?

rosijanka [135]

Answer:

El área es 2 veces el cuadrado del ancho del rectángulo.

Step-by-step explanation:

El área de un rectángulo viene dado por:

$A = a*l$

En donde:

a: es el ancho

l: es el largo

Si el largo es el doble del ancho:

$l = 2a$

Entonces el área es:

$A = a*l = a*(2a) = 2a^{2}$

Por lo tanto, el área es 2 veces el cuadrado del ancho del rectángulo.

Espero que te sea de utilidad!

6 0

3 years ago

The equation 9 x 2 − 12 x + 4 = 0 9 x 2 − 12 x + 4 = 0 has how many different solutions?

Hatshy [7]

We have the equation:

$9x^2-12x+4=0$

so:

$a=9\qquad b=-12\qquad c=4$

and:

$\Delta=b^2-4ac=(-12)^2-4\cdot9\cdot4=144-144=\boxed{0}$

This equation has one solution.

5 0

3 years ago

I need help with these questions for Quadratic functions

STALIN [3.7K]

9514 1404 393

Explanation:

1. The general form of a quadratic in standard form* is ...

$f(x)=ax^2+bx+c$

An example is ...

$f(x)=2x^2+3x-5$

The constant c is the y-intercept, so is the easiest bit of information to obtain in this form.

2. The general form of a quadratic in vertex form can be written as ...

$f(x)=a(x-h)^2+k$

An example is ...

$f(x)=2(x -3)^2 -5$

The ordered pair (h, k) is the vertex of the parabola, so is easy to obtain in this form. Arguably, it may be easier to identify the line of symmetry, x=h, since that requires looking at only one constant, instead of two.

_____

* In the UK, "standard form" is vertex form.

7 0

3 years ago