Answer:
Part A) ΔCGB and ΔPBE are similiar
Part B) They are similar because they are Vertical Angles/Alternate Interior Angles
Part C) Distance from B to E is 125; Distance from P to E is 275.
Step-by-step explanation:
Your answer is $15.28.
I hope that this helps and have a nice day.
Let's see
In ∆ABE and ∆CBE
- BE=BE(Common side)
- AE=EC[Diagonals of a parallelogram bisect each other]
- <AEB=<BEC[90°]
So by
SAS congruence the triangles are congruent
AB=BC
Fact:-
It's already given AC is perpendicular to BD
- It means diagonals are perpendicular to each other
According to general property of rhombus this parallelogram is also a rhombus.
So sides are equal hence AB =BC