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3 years ago

Claire drew a house for her art class. The drawing is shown below.

Mathematics

1 answer:

kompoz [17]3 years ago

3 0

Answer:

I think the answer is A

sorry if i'm wrong

Step-by-step explanation:

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Simplify: (-3x^3+2x^2+4x)-(8x^4-5x^3+6x^2-2x

sergejj [24]

Answer:

−8^4+2^3−4^2+6

Step-by-step explanation:

Distribute the - to 8x^4-5x^3+6x^2-2x:

-8x^4+5x^3-6x^2+2x

Now simplify:

-3x^3+2x^2+4x-8x^4+5x^3-6x^2+2x= −8^4+2^3−4^2+6

Hope this helps!

3 0

3 years ago

Is it...

Art [367]

The transformations done are option A. A reflection over the y-axis, then a reflection over the x-axis

Step-by-step explanation:

Step 1:

First, we plot the points of triangle ABC and A''B''C''.

The points of triangle ABC are A (-8, -5), B(-4, -3), and C(-4,-7).

The points of triangle A''B''C'' are A'' (8, 5), B'' (4, 3), and C'' (4,7).

The points of both triangles ABC and A''B''C'' are the same values but different symbols for x and y values.

Step 2:

If a shape is reflected across an axis, the values remain the same but the symbols vary according to the quadrant.

If a shape is translated, all coordinates of all the points vary accordingly.

As triangles ABC and A''B''C'' have exactly the same coordinates it means that two reflections have occurred but no translations have occurred.

So the answer is the option with two reflections. So option A. A reflection over the y-axis, then a reflection over the x-axis is the answer.

4 0

3 years ago

Find two numbers, if their sum is −11 and their difference is 41

snow_tiger [21]

The larger one is (-11 + 41)/2 = 15.

The smaller one is (-11 -41)/2 = -26.

_____

For two numbers a and b with sum s and difference d, you can write the equations

$a+b=s\\a-b=d$

Then adding the equations and dividing that sum by 2, you get

$(a+b)+(a-b)=(s)+(d)\\2a=s+d\\a=\dfrac{s+d}{2}$

You can subtract the second eqution from the first and get a similar result for the smaller number

$(a+b)-(a-b)=(s)-(d)\\2b=s-d\\b=\dfrac{s-d}{2}$

These are the formulas we used above.

3 0

4 years ago

16. (-4) = what is the answer<br>

kirill115 [55]

Answer

-64

just use ur calculator since my teacher let us use the calculator i just typed in 16.(-4) and got -64

5 0

3 years ago

Read 2 more answers

The top and bottom margins of a poster are each $3$ cm and the side margins are each $2$ cm. If the area of printed material on

babymother [125]

Answer:

Therefore the dimension of the poster is 12 cm by 8 cm.

Step-by-step explanation:

Let the length of the poster be x and the width be y.

Given that the area of the poster is 96 cm².

∴xy =96

$\Rightarrow y= \frac{96}{x}$

The sides margins each are 2 cm and the top and bottom margins of the poster are each 3 cm.

The length of printing space is =(x- 2.3) cm

= (x-6) cm

The width of the printing space is =(y-2.2) cm

=( y-4 )cm

The area of the printing space is A=(x-6)(y-4) cm²

∴A=(x-6)(y-4)

$\Rightarrow A=(x-6)(\frac{96}{x}-4)$ [ Putting $y= \frac{96}{x}$ ]

$\Rightarrow A=120-\frac{576}{x}-4x$

Differentiating with respect to x

$A'= \frac{576}{x^2}-4$

Again differentiating with respect to x

$A''=-\frac{1152}{x^3}$

To find the minimum area, we set A'=0

$\therefore \frac{576}{x^2}-4=0$

$\Rightarrow \frac{576}{x^2}=4$

$\Rightarrow x^2=\frac{576}{4}$

$\Rightarrow x^2 =144$

$\Rightarrow x=\pm 12$

Dimension can't be negative.

Therefore x=12

If x=12, the value of A''>0,then at x=12, the area of the poster will be minimum.

If x=12, the value of A''<0,then at x=12, the area of the poster will be minimum.

$\therefore A''|_{x=12}=-\frac{1152}{12^3}$

Therefore at x= 12 cm the area of the poster will be maximum.

The width of the poster is $y=\frac{96}{12}$ = 8 cm

Therefore the dimension of the poster is 12 cm by 8 cm.

3 0

3 years ago