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Flauer [41]
3 years ago
10

A container has a capacity of 4 quarts. What is the capacity in pints

Mathematics
2 answers:
Firlakuza [10]3 years ago
7 0

Answer: 8 pints

Step-by-step explanation:

Multiply the volume value by 2, so, 4 quarts = 8 pints

Katarina [22]3 years ago
6 0

Answer:

4 quarts=8 pints.

Hope this helps.

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................................................................
Alekssandra [29.7K]

Answer:

A

Answer is A.

Hope this helps.

3 0
3 years ago
NEED HELP ASAP!!!!!!!!!!!!!!!!!!!!!!!! The equal sections of a spinner have one of the following letters: A, B, A, C, B. Predict
Eddi Din [679]

Answer:

the 3rd A

Step-by-step explanation:

ABACB = 5 altogether

ABACB ABA = 8

5 0
3 years ago
Read 2 more answers
Does this table represent a function? why or why not? x: 2 3 3 4 5 y: 1 4 3 2 5
gayaneshka [121]
Let's put the chart into ordered pairs:
(x, y)
(2,1)
(3,4)
(3,3)
(4,2)
(5,5)

In bold, we see that there are two y-values at x=3. This means that this relation fails the vertical line test (two points on the same verticle line). This is not a function. 

The answer options may be mis-written. 
The answer is no, because one x value corresponds to more than one y-value. 
7 0
3 years ago
Read 2 more answers
What is the solution for x in the equation?<br><br> 10x − 4.5 + 3x = 12x − 1.1
Aleksandr [31]

Answer:in first part of equation add 10x and 3x (like terms)

13x-4.5=12x-1.1

move all terms containing x to left side of equation

13x-4.5-12x= -1.1

x-4.5= -1.1

Subtract 4.5 from both sides

x=3.4

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
13 POINTS- please help me
allsm [11]

Answer:

See explanation

Step-by-step explanation:

16. Two parallel lines are cut by transversal. Angles with measures (6x+20)^{\circ} and (x+100)^{\circ} are alternate exterior angles. By alternate exterior angles, the measures of alternate exterior angles are the same:

6x+20=x+100\\ \\6x-x=100-20\\ \\5x=80\\ \\x=16

Then

(6x+20)^{\circ}=(6\cdot 16+20)^{\circ}=116^{\circ}\\ \\(x+100)^{\circ}=(16+100)^{\circ}=116^{\circ}

17. Two parallel lines are cut by transversal. Angles with measures (2x+12)^{\circ} and (3x-22)^{\circ} are alternate interior angles. By alternate interior angles, the measures of alternate interior angles are the same:

2x+12=3x-22\\ \\2x-3x=-22-12\\ \\-x=-34\\ \\x=34

Then

(2x+12)^{\circ}=(2\cdot 34+12)^{\circ}=80^{\circ}\\ \\(3x-22)^{\circ}=(3\cdot 34-22)^{\circ}=80^{\circ}

18. Two parallel lines are cut by transversal. Angles with measures (6x-7)^{\circ} and (5x+10)^{\circ} are alternate exterior angles. By alternate interior angles, the measures of alternate exterior angles are the same:

6x-7=5x+10\\ \\6x-5x=10+7\\ \\x=17

Then

(6x-7)^{\circ}=(6\cdot 17-7)^{\circ}=95^{\circ}\\ \\(5x+10)^{\circ}=(5\cdot 17+10)^{\circ}=95^{\circ}

19. The diagram shows two complementary angles with measures 2x^{\circ} and 56^{\circ}. The measures of complementary angles add up to 90^{\circ}, then

2x+56=90\\ \\2x=90-56\\ \\2x=34\\ \\x=17

Hence,

2x^{\circ}=2\cdot 17^{\circ}=34^{\circ}

Check:

34^{\circ}+56^{\circ}=90^{\circ}

20. Angles \angle 1 and \angle 2 are vertical angles. By vertical angles theorem, vertical angles are congruent, so

m\angle 1=m\angle 2\\ \\5x+7=3x+15\\ \\5x-3x=15-7\\ \\2x=8\\ \\x=4

Hence,

m\angle 1=(5x+7)^{\circ}=(5\cdot 4+7)^{\circ}=27^{\circ}\\ \\m\angle 2=(3x+15)^{\circ}=(3\cdot 4+15)^{\circ}=27^{\circ}

21. \angle 5 and \angle 8 are supplementary. The measures of supplementary angles add up to 180^{\circ}, so

m\angle 5+m\angle 8=180^{\circ}\\ \\3x-40+7x-120=180\\ \\10x-160=180\\ \\10x=180+160\\ \\10x=340\\ \\x=34

Therefore,

m\angle 5=(3x-40)^{\circ}=(3\cdot 34-40)^{\circ}=62^{\circ}\\ \\m\angle 8=(7x-120)^{\circ}=(7\cdot 34-120)^{\circ}=118^{\circ}\\ \\62^{\circ}+118^{\circ}=180^{\circ}

7 0
3 years ago
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