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Aloiza [94]
3 years ago
6

Someone help plz, I'm stuck

Mathematics
1 answer:
VladimirAG [237]3 years ago
6 0

Answer:

Original price reduced by 30%

Step-by-step explanation:

You want the deepest discount, which means you want the greatest percent/amount off. The first choice is 20%. The second is 30%. The third one is 25%, because you are paying for 75% (100-75). The second choice offers the deepest discount because it is 30% off.

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The figure shows a triangle with its three angle bisectors intersecting at Point P.
NeX [460]

Check the picture below.

we know the lines are angle bisectors, so the line makes twin angles, so the line FP is making twin angles, we also know the angle FZP and the angle FYP are right-angles, as well as FP is a common hypotenuse to two right triangles, thus by the HA postulate for right triangles, triangle FPZ and triangle FPY are both congruent, so their sides are also congruents, thus PY = PZ.

7 0
3 years ago
A rocking horse has a weight limit of 60pounds. What percentage of the weight limit is 33 pounds? What percentage of the weight
bixtya [17]

Answer:

The percentage is <u>55%</u> when weight limit is 33 pounds.

The percentage is <u>190%</u> when weight limit is 114 pounds.

The 95% of the limit weighs <u>57</u> pounds.

Step-by-step explanation:

Given:

Weight limit of rocking horse = 60 pounds.

We need to find:

a) What percentage of the weight limit is 33 pounds.

b)What percentage of the weight limit is 114 pounds.

c) What weight is 95% of the limit.

Now Solving for a we get;

Weight limit = 33 pounds

Now percentage of the weight limit can be calculated by dividing given weight limit with total weight limit and then multiplying by 100 we get;

framing in equation form we get;

percentage of the weight limit = \frac{33}{60}\times100 = 55\%

Hence The percentage is <u>55%</u> when weight limit is 33 pounds.

Now Solving for b we get;

Weight limit = 114 pounds

Now percentage of the weight limit can be calculated by dividing given weight limit with total weight limit and then multiplying by 100 we get;

framing in equation form we get;

percentage of the weight limit = \frac{114}{60}\times100 = 190\%

Hence The percentage is <u>190%</u> when weight limit is 114 pounds.

Now Solving for c we get;

Percentage Weight = 95%

Now Amount of weight limit can be calculated by multiplying Percentage weight limit with total weight limit and then Dividing by 100 we get;

framing in equation form we get;

percentage of the weight limit = \frac{95}{100}\times60 = 57 \pounds

Hence The 95% of the limit weighs <u>57</u> pounds.

4 0
4 years ago
Iterations question two need help please :)
Contact [7]

Answer:

option b

1 , 16, 121 , 13456

Step-by-step explanation:

Given in the question a function, f(x) = (x - 5)²

initial value x_{0} = 4

First iteration

f(x0) = f(4) = (4 - 5)² = (-1)² = 1

x1 = 1

Second iteration

f(x1) = f(1) = (1 - 5)² = (-4)² = 16

x2 = 16

Third iteration

f(x2) = f(16) = ( 16 - 5)² = (11)² = 121

x3 = 121

Fourth iteration

f(x3) = f(121) = (121 - 5)² = (116)² = 13456

x4 = 13456

 

8 0
3 years ago
M= 1/2 and point : (4,-3) <br><br> Please help I will give you brainless
Vlad1618 [11]

Answer:

y=1/2x-5

Step-by-step explanation:

We have slope so we just need to find the y intercept.

slope intercept formula is

y=mx+b

(m) is slope

(b) is y int

y=1/2x+b

now apply our given x and y values (4 & -3)

-3=1/2(4)+b

simplify

-3=2+b

subtract 2 from each side

-5=b

put that into our equation

y=1/2x-5

6 0
3 years ago
Cual es la magnitud de la aceleración angular de una llanta de un automóvil que adquiere una velocidad angular de 350 rad/s en 2
drek231 [11]

Respuesta:

175 rad / s²

Explicación paso a paso:

Dado que :

Velocidad angular final = 350 rad / s

Tiempo empleado = 2 segundos

La aceleración angular, a =?

Recordar ; la aceleración angular es igual a la carga en velocidad angular con el tiempo

(velocidad final - Velocidad inicial) / tiempo empleado

Velocidad inicial = 0 rad / s

Aceleración angular = (350 - 0) / 2 = 350/2

= 175 rad / s²

3 0
3 years ago
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