Answer:
x= 5
Step-by-step explanation:
3x² - 21
Factor 3 from both terms:
3 (x² - 7)
To me, that's as far as you should need to go. But if you want to get
completely carried away, you could go one step further, since you have
the difference of two squares:
3 (x + √7) (x - √7)
Of course, there's no end now, because the last binomial could be
considered another difference of two squares, so you'd have to
factor that too:
3 (x + √7) (√x + ⁴√7) (√x - ⁴√7)
but to me, this would be nonsense.
Find the area of the triangles and smal ler square and add them together ; and find the area of the complete square and set them equal to each other (these are known truths)
triangle: l×w /2
square: s^2
There are 4 triangles so
4 (1/2ab)+c^2= (a+b)(a+b)
simplify
2ab+c^2= a^2+2ab+b^2
-2ab both sides
c^2=a^2+b^2
tada!! it's proven :)
If tan theta is -1, we know immediately that theta is in either Quadrant II or Q IV. We need to focus on Q IV due to the restrictions on theta.
Because tan theta is -1, the ray representing theta makes a 45 degree angle with the horiz axis, and a 45 degree angle with the negative vert. axis. Thus the hypotenuse, by the Pythagorean Theorem, tells us that the hyp is sqrt(2).
Thus, the cosine of theta is adj / hyp, or +1 / sqrt(2), or [sqrt(2)]/2
The secant of theta is the reciprocal of that, and thus is
2 sqrt(2)
---------- * ------------ = sqrt(2) (answer)
sqrt(2) sqrt(2)
Answer:
d
Step-by-step explanation:
There is not enough information to solve this question