The length of GH is 15.
<h3>How to calculate the length?</h3>
GH = IG
GH = 5x - 10
IG = 3x
5x - 10 = 3x
5x - 3x = 10
2x = 10
x = 10/2 = 5
GH = 5x - 10
= 5 * 5 - 10 = 25 - 10
GH = 15
<ABD = < DBC
<ABD = 10y°
<DBC = (8y + 4)°
10y° = (8y + 4)°
10y = 8y + 4
10y - 8y = 4
2y = 4
y = 4/2 = 2
The value of y is 2
<DBE = <DBC + <CBE
<DBC = 10y°
<CBE = <DBC = 10y°
y = 2
<DBC = <CBE = 10y° = 10*2° = 20°
<DBE = 20° + 20° = 40°
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$120 per each student x 495 students = $59,400
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5y
...............,l,l,l,l,l,l,l
Answer:
37 units
Step-by-step explanation:
The horizontal distance between these two points is 35 and the vertical is 12.
Treat these distances as the lengths of the legs of a right triangle whose hypotenuse we want to determine:
d^2 = 35^2 + 12^2 = 1369, so d = the distance between these two points = d = sqrt(1369) = 37 units