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Levart [38]
3 years ago
7

A copy machine is set to enlarge an image 160%. If the original image is 3 inches tall, how

Mathematics
1 answer:
Mamont248 [21]3 years ago
4 0

Answer:

The enlarged image will be about 4.8 inches

Step-by-step explanation:

Here, we want to know how tall the image will be

Mathematically;

That will simply be 160% of 3 inches

We have;

160/100 * 3 = 480/100 = 4.8 inches

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Dvinal [7]

Answer:

1/25

Step-by-step explanation:

= 5^4/5^6

= 1/5^6-4

= 1/5^2

= 1/25

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How to put 24.357 in expanded form?
muminat
20 + 4 + 3/10 + 5/100 + 7/1000
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3 years ago
3 3/5 + 9 3/5 answer with a mixed number in simplest form
Romashka [77]

Both fractions have the same denominator so it's going to be easy. First set up your equation:

3 \frac{3}{5} + 9 \frac{3}{5}

Add the whole numbers:

3 + 9 = 12

Now add the fractions:

\frac{3}{5} + \frac{3}{5} = \frac{6}{5}

add both together:

12 + \frac{6}{5} = 12 \frac{6}{5}

\frac{6}{5} is an improper fraction so change it:

12 \frac{6}{5} = 13 \frac{1}{5}

Since 6 is one more than 5, add 1 to the whole number and subtract the numerator and denominator(6 - 5 = 1) and make the remaining the new numerator. That leaves you with 13 \frac{1}{5}

Your answer is 13 \frac{1}{5}

3 0
3 years ago
Dan played in 7 basketball games. Altogether he scored 72 field goals (2 points each) and 9 free throws (1 point each). Find the
liubo4ka [24]
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6 0
3 years ago
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10. Three kinds of teas are worth $4.60 per pound, $5.75 per pound, and $6.50 per pound. They are to be
zepelin [54]

Answer:

The mass of the $4.60/lb tea that should be used in the mixture is 10 lb

The mass of the $5.75/lb tea that should be used in the mixture is 8 lb

The mass of the $6.50/lb tea that should be used in the mixture is 2 lb

Step-by-step explanation:

The parameters of the question are;

The worth of the three teas are

Tea A = $4.60/lb

Tea B = $5.75/lb

Tea C = $6.50/lb

The mass of the mixture of the three teas = 20 lb

The worth of the mixture of the three teas = $5.25 per pound = $5.25/lb

The amount of the $4.60 in the mixture = The sum of the amount of the other two teas

Therefore, given that the mass of the mixture = 20 lb, we have in the mixture;

The mass of tea A + The mass of Tea B + The mass of Tea C = 20 lb

The mass of tea A = The mass of Tea B + The mass of Tea C

Therefore;

The mass of tea A + The mass of tea A = 20 lb

2 × The mass of tea A in the mixture = 20 lb

The mass of tea A in the mixture = 20 lb/2 = 10 lb

The mass of tea A in the mixture = 10 lb

The mass of Tea B + The mass of Tea C = The mass of tea A = 10 lb

The mass of Tea B + The mass of Tea C = 10 lb

The mass of Tea B  = 10 lb - The mass of Tea C

Where the mass of Tea C in the mixture = x, we have;

The mass of Tea B in the mixture = 10 lb - x

The cost of the 10 lb of tea A = 10 × $4.60 = $46.0

The worth of the tea mixture = 20 × $5.25 = $105

The worth of the remaining 10 lb of the mixture comprising of tea A and tea B is given as follows;

The worth of Tea B + The worth of Tea C in the mixture = $105.00 - $46.00 = $59.00

Therefore, we have;

x lb × $6.50/lb + (10 - x) lb × $5.75/lb = $59.00

x × $6.50 - x × $5.75 + $57.50 = $59.00

x × $0.75 = $59.00 -  $57.50 = $1.50

x =  $1.50/$0.75 = 2 lb

∴ The mass of Tea C in the mixture = 2 lb

The mass of Tea B in the mixture = 10 lb - x = 10 lb - 2 lb = 8 lb

The mass of Tea B in the mixture = 8 lb

Therefore, since we have;

Tea A = $4.60/lb

Tea B = $5.75/lb

Tea C = $6.50/lb

The mass of tea A in the mixture = 10 lb

The mass of tea B in the mixture = 8 lb

The mass of tea C in the mixture = 2 lb, we find;

The mass of the $4.60/lb tea that should be used in the mixture = 10 lb

The mass of the $5.75/lb tea that should be used in the mixture = 8 lb

The mass of the $6.50/lb tea that should be used in the mixture = 2 lb.

6 0
3 years ago
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