As per your question, total cost of watermelon should end with either 5(for odd quantity) or 0(for even quantity).
If the quantity of watermelon is odd, then the total cost value of pineapple should end with 3 and this is not possible when the cost of pineapple is ₹7.
So let's come to conclusion that the count(quantity) of watermelon should be any one of 0, 2, 4, 6.
If count of watermelon is 6: It will cost ₹30 and for remaining ₹8, we can buy 1 pineapple but still ₹1 will not be utilised. So 1 pineapple is not possible
If count of watermelon is 4: It will cost ₹20 and for remaining ₹18, we can buy 2 pineapple with ₹4 not being utilised. So 2 pineapple is also not possible.
If count of watermelon is 2: It will cost ₹10 and for remaining ₹28, we can buy 4 pineapple with all amount being utilised. We can buy 4 pineapple along with with 2 watermelon for ₹38.
If count of watermelon is 0: It will cost you ₹0 and for remaining ₹38, we can buy 5 pineapple with ₹3 being not utilised. So 5 pineapple is also not possible.
So the answer is 4 pineapple.
Answer:
I hope it will help you...
We know is a horizontal line, so, if it passes through 1,-5, it also passes through "whatever", -5, like 20, -5 or 1000000, -5, or -100000000, -5 and so on.
so, let's pick another point say -7, -5, check the picture below, and let's check about the equation that runs through it,
Answer: m=−3
Step-by-step explanation: −40−2(3m+1/2)=7m−2
−40+(−2)(3m)+(−2)(1/2)=7m+−2
−40+−6m+−1=7m+−2
(−6m)+(−40+−1)=7m−2
−6m+−41=7m−2
−6m−41−7m=7m−2−7m
−13m−41+41=−2+41
−13m/−13=39/−13
m=−3
What mistake I guess Keith did make is he subtracted 2 from -39 which equaled to -37 which caused him divide -37 by 13 when it should have been 39 divided by 13 because he should have left 39 alone and not have subtracted 2 from it also it should not have been negative basically what I'm trying to say is that he did his division and subtraction wrong.
Answer:
Realmente no lo se.
Step-by-step explanation:
Realmente no lo se. no sé. así que sí, lo siento, no puedo ayudar.
