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3 years ago

Can anyone help me with this

Mathematics

2 answers:

tangare [24]3 years ago

7 0

C is the answer because it is.

kolbaska11 [484]3 years ago

3 0

The correct answer is C.

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16d - (4 - 5d) = -67 Please help me find d

madreJ [45]

$16d-(4-5d)=-67\\\\16d-4-(-5d)=-67\\\\16d-4+5d=-67\\\\21d-4=-67\ \ \ \ /+4\\\\21d-4+4=-67+4\\\\21d=-63\ \ \ \ /:21\\\\21d:21=-63:21\\\\d=-3$

5 0

3 years ago

Read 2 more answers

Least to greatest please

Diano4ka-milaya [45]

Answer:

Step-by-step explanation:

Answer is B.

Square root of 10 is 3.16.

3 and one fourth is 3.25.

3.12, 3.16, 3.24, 3.25

7 0

3 years ago

Please help me with these, oh sweet jesus

Lelechka [254]

Answer:

77. $\cot^{6} x = \cot^{4} x \csc^{2}x - \cot^{4} x$ Proved

78. $\sec^{4}x \tan^{2} x = \sec^{2}x [\tan^{2}x + \tan^{4}x ]$ Proved

79. $\cos^{3} x\sin^{2} x = [\sin^{2}x - \sin^{4}x] \cos x$ Proved.

80. $\sin^{4}x - \cos^{4}x = 1 - 2\cos^{2}x + 2 \cos^{4} x$ Proved.

Step-by-step explanation:

77. Left hand side

= $\cot^{6} x$

= $\cot^{4} x \times \cot^{2} x$

= $\cot^{4}x [\csc^{2}x - 1]$

{Since we know, $\csc^{2} x - \cot^{2}x = 1$ }

= $\cot^{4} x \csc^{2}x - \cot^{4} x$

= Right hand side (Proved)

78. Left hand side

= $\sec^{4}x \tan^{2} x$

= $\sec^{2} x [1 + \tan^{2}x] \tan^{2} x$

{Since $\sec^{2}x - \tan^{2}x = 1$ }

= $\sec^{2}x [\tan^{2}x + \tan^{4}x ]$

= Right hand side (Proved)

79. Left hand side

= $\cos^{3} x\sin^{2} x$

= $\cos x[1 - \sin^{2} x] \sin^{2} x$

{Since $\sin^{2}x + \cos^{2} x = 1$ }

= $[\sin^{2}x - \sin^{4}x] \cos x$

= Right hand side

80. Left hand side

= $\sin^{4}x - \cos^{4}x$

= $[\sin^{2}x + \cos^{2}x]^{2} - 2\sin^{2} x \cos^{2}x$

{Since $\sin^{2}x + \cos^{2} x = 1$ }

= $1 - 2\cos^{2} x[1 - \cos^{2}x ]$

= $1 - 2\cos^{2}x + 2 \cos^{4} x$

= Right hand side. (Proved)

7 0

3 years ago

I need help on this

Naily [24]

Answer:x=90° y=58° z=32°

Step-by-step explanation:

x=90

y=180-(90+32) sum of angles in a triangle is 180

y=58

y+90+z=180 they are supplementary

58+90+z=180

148+z=180

z=180-148

z=32

5 0

4 years ago

What are the solutions of the quadratic equation? Solve by factoring. 4x^2-18x+20=0

Romashka-Z-Leto [24]

Answer:

x = 5/2,2

Step-by-step explanation:

3 0

3 years ago