Answer:
It will leave the sprinkler at speed of
Step-by-step explanation:
We have given internal diameter of the garden hose
So radius
So area
Water in the hose has a speed of 4 ft/sec
So
Number of holes n = 36
Diameter of each hole
So radius
So area
From continuity equation
It's easy once you spot the ones that can cross cancel!
Say we have the fractions 8/10 and 20/23. (it's easier to see on top of each other)
If you look diagonally , so 8 and 23 and 10 and 20, you can see that 10 and 20 have a common factor. So we divide it by the highest common factor to reduce those numbers, making it easier to multiply. 10 and 20 can become 1 and 2, dividing by 10. So now we are left with 8/1 and 2/23, and now we multiply normally going across so 16/23.
This works going both diagonals and simplifying both, but in that case it would be easier to try and simplify the fractions before cross multiplying them.
Basically: look for those diagonals and if they can be divided down by the highest common factor, go for it to make it easier to multiply normally afterwards.
Hope I helped!