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AnnZ [28]
3 years ago
13

Please help!!!!!!!!!!!!

Mathematics
2 answers:
ddd [48]3 years ago
8 0
1.4*10 2nd power = 1400000000
8.25*10 2nd power = 825
1400000000*825= 1155000000000
vazorg [7]3 years ago
3 0

Answer:

Since 10 to the ninth power is 1000000000 and 1000000000 times 1.4 is 1400000000 and 10 to the second power is 100 and 100 times 8.25 is 825 you would subtract 1400000000 and 825 and get the answer of 1399999175.

*this might be wrong*

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A number decreased by 9 is 12. Which equation represents this situation?
Mice21 [21]

Answer:

x - 9 = 12

Step-by-step explanation:

We can use x as "a number"

So the equation so far is just "a number", or x.

Decreased by 9 can also be said as subtracted by 9, so that makes the equation x - 9.

"is 12" can also be said as equals 12, which makes the equation x - 9 = 12

4 0
3 years ago
Read 2 more answers
A certain forest covers an area of
iVinArrow [24]

Answer:

2598 square kilometers

Step-by-step explanation:

Hello

Step 1

year one

using a rule of three is possible to find how much is 8.75 od 4500 km2

Let

if

4500 km2  ⇒ 100$

x?km2         ⇒8.75

do the relation and isolate x

4500:100\\x:8.75\\\frac{4500}{100}=\frac{x}{8.75}\\x=\frac{4500*8.75}{100} \\x=393.75\\

at the end of the year one, the area will be

4500-393.75=4106.25

this will be the initial area for the year 2.

Step 2

repite the step 1 with area initial =4106.25 km2

4106.25 km2  ⇒ 100$

x?km2         ⇒8.75

do the relation and isolate x

4106.25:100\\x:8.75\\\frac{4106.25}{100}=\frac{x}{8.75}\\x=\frac{4106.25*8.75}{100} \\x=359.29\\

at the end of the year 2, the area will be

4106-359.29=3746.70

this will be the initial area for the year 3.

Step 3

repite the step 1 with area initial =4106.25 km2

3746.70 km2  ⇒ 100$

x?km2         ⇒8.75

do the relation and isolate x

3746.70:100\\x:8.75\\\frac{3746.70}{100}=\frac{x}{8.75}\\x=\frac{3746.7*8.75}{100} \\x=327.83\\

at the end of the year 3, the area will be

3746.70-327.83=3419.09

this will be the initial area for the year  4.

Step 4

year four

repite the step 1 with area initial =3419.09 km2

3419.09 km2  ⇒ 100$

x?km2         ⇒8.75

do the relation and isolate x

3419.09:100\\x:8.75\\\frac{3419.09}{100}=\frac{x}{8.75}\\x=\frac{3419.09*8.75}{100} \\x=299.17\\

at the end of the year 4, the area will be

3419.09-299.173=3119.82

this will be the initial area for the year  5.

Step 5

year five

repite the step 1 with area initial =3119.82 km2

3119.82 km2  ⇒ 100$

x?km2         ⇒8.75

do the relation and isolate x

3119.82:100\\x:8.75\\\frac{3119.82}{100}=\frac{x}{8.75}\\x=\frac{3119.82*8.75}{100} \\x=272.99\\

at the end of the year 5, the area will be

3119.82-272.99=2846.92

this will be the initial area for the year  6.

Step 6

year six

repite the step 1 with area initial =2846.92km2

2846.92 km2  ⇒ 100$

x?km2         ⇒8.75

do the relation and isolate x

2846.92:100\\x:8.75\\\frac{2846.92}{100}=\frac{x}{8.75}\\x=\frac{2846.92*8.75}{100} \\x=249.10\\

at the end of the year six, the area will be

2846.92-249.10=2597.82 square kilometers

Have a great day.

8 0
3 years ago
Line CD is the perpendicular bisector of segment AB. The lines intersect at point E. Which of these statements is true?
fredd [130]

Answer:

C. E is the same distance from A and B.

Step-by-step explanation:

Line CD is a perpendicular that divides segment AB into two equal parts as it intersects segment AB at point E.

This divides AB into AE and EB.

Point E is the middle of A and B. Therefore, E will be the same distance from A and from B.

That is, AE = EB.

Therefore, the statement that is true is: C. E is the same distance from A and B.

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Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre
tia_tia [17]
Well there’s no picture sooo
7 0
4 years ago
If Paul is 2 times older than matt and matt it two times older than Charles ( age 12 ) how old is Paul?
max2010maxim [7]
Charles is twelve. Matt is two times older so he is 24. Paul is two times older than Matt so he is 48.
5 0
3 years ago
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