Answer:
2
Step-by-step explanation:
It sounds like we are pretending A is the universe. The only numbers in our world are 1,2,3,4, and 5.
You are given B is all numbers greater than 2.
The complement of B would all the elements not listed in B.
The elements in B are 3,4, and 5, since we are looking for numbers greater than 2 in our world of numbers above.
The elements not in B are 1 and 2.
So B complement is {1,2}.
There are 2 elements in our set for B complement. The elements that were counted were just the element 1 and the element 2.
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Answer:
10ft
Step-by-step explanation:
The solution to the first expression - 7+3(9-4)^2÷5 is given as 22.
To get the answer correctly, one must follow rudimentary rules of operations which are coined into the acronym BODMAS.
<h3>What is BODMAS?</h3>
This is the order in which mathematical operations must be executed.
B = Bracket
O = Orders (that is Powers, Indices or roots)
D= Division
M = Multiplication
A = Addition
S = Subtraction
Now lets see how we got 22 from the first set of operations:
<h3>Operation 1 (Example)</h3>
7+3(9-4)^2÷5 =
7+3 (5)^2÷5=
7+3 * 25÷5 =
7+3*5=
7+15=
22
Following the BODMAS rule and the example in Operation 1 above, we can state the remaining answers as follows:
<h3>
Operation 2</h3>
12/3-4+7^2 = 49
<h3 /><h3>
Operation 3</h3>
(7-3)×3^3÷9 = 12
<h3>Operation 4</h3>
5(7-3)^2÷(6-4)^3-9 = 1
<h3>Operation 5</h3>
3×(7-5)^3÷(8÷4)^2-5 = 1
<h3>Operation 6</h3>
9+(3×10)/5×2-12 = 9
See the link below for more about Mathematical Operations:
brainly.com/question/14133018
