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RSB [31]
3 years ago
9

Write the expression as a monomial in its standard form: (–c^2)^3·0.15c^4

Mathematics
1 answer:
dedylja [7]3 years ago
3 0

(–c^2)^3*.15c^4

power to a power in exponents is multiply

(–c^2)^3 = (-c^ 6)

= -c^6

-c^6  *.15 c^4

when multiply exponents add the exponents , multiply the coefficients

(-1*.15)c^(6+4)

=-.15 c^(10)


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I am confused in these problems ?<br>8. 9.
Liula [17]

Answer:

8. 14

9. 720

Step-by-step explanation:

Both questions are asking you to find the GCD (Greatest Common Divisor) and LCM (Lowest Common Multiple).

8. Find the greatest number that can divide 392 and 462 exactly.

Find the GCD of 392 and 462:

  1. Find the prime factorization of 392

2^3 × 7^2 (2 × 2 × 2 × 7 × 7)

  2. Find the prime factorization of 462

2 × 3 × 7 × 11

  3. To find the GCD, multiply all prime factors common to all numbers  

GCF = 2 × 7, therefore GCD = 14.

9. What is the smallest number that is divisible by 20, 48, and 72?

Find the LCM of 20, 48, and 72:

  1. Find the prime factorization of 20

2^5 (2 × 2 × 5)

  2. Find the prime factorization of 48

2^4 x 3 (2 × 2 × 2 × 2 × 3)

  3. Find the prime factorization of 72

2^3 x 3^2 (2 × 2 × 2 × 3 × 3)

  4. To find the LCM, multiply all prime factors

LCM = 2^4 × 3^2 × 5 (2 × 2 × 2 × 2 × 3 × 3 × 5), therefore GCF = 720

Calculator Input:

The easiest way to find the GCD or LCM of 2 or more numbers is by using a scientific calculator. Input GCD(x,y) or LCM(x,y) for the answer. This will work for any amount of numbers as long as the input is logical.

For questions 8 and 9, you would type in GCD(392,462) and LCM(20,48,72).

Not all calculators are made the same, so other labels might be GCF or HCF instead of GCD, and LCF instead of LCM. I use GCD and LCM because that's how it is on my calculator. There isn't any difference, so using any label is fine.

5 0
2 years ago
A credit card had an APR of 17.84% all of last year and compounded interest daily. What was the credit card's effective interest
Andreas93 [3]
The solution to the problem is as follows:

<span>((1+.1784/365)^365) - 1 =.1953=19.53%
</span>
Therefore, best and most correct answer among the choices provided by your question is the fourth choice or letter D. 19.53%

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
3 0
3 years ago
Read 2 more answers
The lives of a premium sports car's brakes are normally distributed with a mean of 60,000 miles and a standard deviation of 4,00
dedylja [7]

Answer:

86.64% probability that such brakes last between 54,000 and 66,000 miles

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 60000, \sigma = 4000

What is the probability that such brakes last between 54,000 and 66,000 miles?

This is the pvalue of Z when X = 66000 subtracted by the pvalue of Z when X = 54000.

X = 66000

Z = \frac{X - \mu}{\sigma}

Z = \frac{66000 - 60000}{4000}

Z = 1.5

Z = 1.5 has a pvalue of 0.9332

X = 54000

Z = \frac{X - \mu}{\sigma}

Z = \frac{54000 - 60000}{4000}

Z = -1.5

Z = -1.5 has a pvalue of 0.0668

0.9332 - 0.0668 = 0.8664

86.64% probability that such brakes last between 54,000 and 66,000 miles

7 0
3 years ago
Grace is going to a carnival that has games and rides. Each game costs $1.50 and each ride costs $2.50. Grace spent $16.50 altog
victus00 [196]

Answer:

  • g=games; r=rides
  • 1.5g +2.5r = 16.5
  • g = 2r

Step-by-step explanation:

Let g and r represent the numbers of games played and rides ridden, respectively. Then the system can be written ...

  1.50g +2.50r = 16.50 . . . . . total amount spent

  g = 2r . . . . . . . . . . . . . . . . . . relationship of games to rides

8 0
3 years ago
Read 2 more answers
david counts the quarters in his change jar. He has 24 more quarters than his brother Rob. if r is the number of quarters Rob ha
denis-greek [22]
Rob has R quarters, and David has R + 24 or 24 more than rob, so together they have 2R+24
8 0
4 years ago
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