All categories

3 years ago

HELP PLEASE!! thanks

Mathematics

1 answer:

Vesna [10]3 years ago

5 0

Answer:

352

but for the 3 it would be 264

You might be interested in

The diagram shows a right-angled triangle.

Margarita [4]

1/sin(38)*7=11.4
Hope it helps

6 0

3 years ago

Please help with this

timurjin [86]

Answer:

Hey mate.....

Step-by-step explanation:

This is ur answer.....

Step 1 :-

Step 2 :-

Hope it helps!

Follow me! ;)

4 0

2 years ago

What type of triangle has an exterior angle that is obtuse at to vertices?

Norma-Jean [14]

An exterior angle of a triangle is equal to the sum of the two opposite interior angles. Example : Find the values of x and y in the following triangle. y + 92° = 180° (interior angle + adjacent exterior angle = 180°.)

7 0

3 years ago

Determine the number of possible solutions for a triangle with B=37 degrees, a=32, b=27

vladimir1956 [14]

Answer:

Two possible solutions

Step-by-step explanation:

we know that

Applying the law of sines

$\frac{a}{sin(A)}=\frac{b}{Sin(B)}=\frac{c}{Sin(C)}$

we have

$a=32\ units$

$b=27\ units$

$B=37\°$

step 1

Find the measure of angle A

$\frac{a}{sin(A)}=\frac{b}{Sin(B)}$

substitute the values

$\frac{32}{sin(A)}=\frac{27}{Sin(37\°)}$

$sin(A)=(32)Sin(37\°)/27=0.71326$

$A=arcsin(0.71326)=45.5\°$

The measure of angle A could have two measures

the first measure-------> $A=45.5\°$

the second measure -----> $A=180\°-45.5\°=134.5\°$

step 2

Find the first measure of angle C

Remember that the sum of the internal angles of a triangle must be equal to $180\°$

$A+B+C=180\°$

substitute the values

$A=45.5\°$

$B=37\°$

$45.5\°+37\°+C=180\°$

$C=180\°-(45.5\°+37\°)=97.5\°$

step 3

Find the first length of side c

$\frac{a}{sin(A)}=\frac{c}{Sin(C)}$

substitute the values

$\frac{32}{sin(37\°)}=\frac{c}{Sin(97.5\°)}$

$c=Sin(97.5\°)\frac{32}{sin(37\°)}=52.7\ units$

therefore

the measures for the first solution of the triangle are

$A=45.5\°$ , $a=32\ units$

$B=37\°$ , $b=27\ units$

$C=97.5\°$ , $b=52.7\ units$

step 4

Find the second measure of angle C with the second measure of angle A

Remember that the sum of the internal angles of a triangle must be equal to $180\°$

$A+B+C=180\°$

substitute the values

$A=134.5\°$

$B=37\°$

$134.5\°+37\°+C=180\°$

$C=180\°-(134.5\°+37\°)=8.5\°$

step 5

Find the second length of side c

$\frac{a}{sin(A)}=\frac{c}{Sin(C)}$

substitute the values

$\frac{32}{sin(37\°)}=\frac{c}{Sin(8.5\°)}$

$c=Sin(8.5\°)\frac{32}{sin(37\°)}=7.9\ units$

therefore

the measures for the second solution of the triangle are

$A=45.5\°$ , $a=32\ units$

$B=37\°$ , $b=27\ units$

$C=8.5\°$ , $b=7.9\ units$

6 0

3 years ago

The the length of a rectangle is 9 centimeters less than four timesfour times its width. its area is 28 square centimeters. find

wel

Let w = width

then

5w-3 = length

w(5w-3) = 14

5w^2-3w = 14

5w^2-3w-14=0

(5w+7)(w-2) = 0

w = {-7/5, 2}

throw out the negative solution leaving

w = 2 centimeters

length:

5w-3 =5(2)-3 =10-3 = 7 centimeters

4 0

3 years ago