Let D be dogs and C be cats
<em>dogs, d, is initially five less than twice the number of cats, c</em>
D + 5 = 2C
<em>If she decides to add three more of each, the ratio of cats to dogs will be</em>
D + 8 = 2C + 3
<em>Could Bea's Pet Shop initially have 15 cats and 20 dogs?</em>
Simply plug in the numbers
20 + 5 = 2(15)
This is clearly not true: 25 does not equal 30
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Answer:
x = 11
Step-by-step explanation:
Using Secants ad Segments Theorem we can say;
(x + 7) (7) = (15 + 6) (6)
7x + 49 = (21) (6)
7x + 49 = 126
7x = 77
x = 11
Hope this helps!
Answer:
i would say by 7 not 100% sure sorry if it doesnt help :( im trying
Step-by-step explanation:
Change the fractions so they have common denominators. For example. If adding 4/8 + 2/3, a common denominator of the two could be 24. Change both fractions to have a denominator of 24. To do this:
(4/8)×(3/3)= 12/24
(2/3)×(8/8)=16/24
Now that both fractions have denominators of 24, you can simply add the numerators to get your answer. in this case, it would be 28/24
Answer: Ix - 4I ≤ 4
Step-by-step explanation:
You can see a black dot in the zero, and a black dot in the 8.
So those are the extremes of our set and are included in the set of solutions, we have that the set is defined by:
0 ≤ x ≤ 8.
Now we want to construct an absolute value equation such that the set {0 ≤ x ≤ 8} is the set of solutions.
The first step is to find the middle value of that set:
The middle value is equal to half of the difference between the extremes:
m = (8 - 0)/2 = 4.
Now we know the middle point, so we can write the equation:
Ix - mI ≤ m
m = 4
Ix - 4I ≤ 4
That is our inequality.
Where the "equal" part of ≤ is for the values x = 0 and x = 8.
