Answer:
The value of entropy change for the process
Explanation:
Mass of the ideal gas = 0.0027 kilo mol
Initial volume = 4 L
Final volume = 6 L
Gas constant for this ideal gas ( R ) =
Where = Universal gas constant = 8.314
⇒ Gas constant R = 8.314 × 0.0027 = 0.0224
Entropy change at constant temperature is given by,
Put all the values in above formula we get,
This is the value of entropy change for the process.
Answer:
I think it's A,C,E.
Explanation:
I'm not 100% sure, but I think their right, hopefully.
1:A 2:C 3:D YO ABLO ESPANOL PERO ESTA ES LA REPUESTA
Answer:
C) nonmetal
Explanation:
Given;
The sample is in liquid state and do not conduct electricity.
We have given four types of classification.So for first,
A) Ionic
Ionic compounds are found in solid state at room temperature and it conducts electricity when dissolved in water. Hence the sample could not be ionic.
B)Metal
Metals are found in solid state at room temperature except mercury and it conducts electricity very well. Mercury also conducts electricity.So the sample is not a metal.
C)Nonmetal
Non metals are found in solid state except bromine which is in liquid state at room temperature and it does not conducts electricity.
Here the property of nonmetal matches with the sample, so the sample is a nonmetal and it could be Bromine.
D)Salt
Salt is an ionic compound found in solid state at room temperature and it conducts electricity when dissolved in water. Hence the sample could not be salt.
Answer:
The amount of P₄S₃ produced is 0.16 moles.
Explanation:
The balanced reaction is:
8 P₄ + 3 S₈ → 8 P₄S₃
By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate:
- P₄: 8 moles
- S₈: 3 moles
- P₄S₃: 8 moles
Being the molar mass of each compound:
- P₄: 123.895 g/mol
- S₈: 256 g/mol
- P₄S₃: 220.093 g/mol
then by stoichiometry of the reaction, the following amounts of reactant and product participate in the reaction:
- P₄: 8 moles* 123.895 g/mol= 991.16 g
- S₈: 3 moles* 256 g/mol= 768 g
- P₄S₃: 8 moles* 220.093 g/mol= 1,760.744 g
The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.
In this case, you calculate the limiting reactant using the following rule of three: if by stoichiometry 768 g of S₈ react with 991.16 g of P₄, 40 g of S₈ with how much mass of P₄ will it react?
mass of P₄= 51.62 grams
But 51.62 grams of P₄ are not available, 20 grams are available. Since you have less mass than you need to react with 40 grams of S₈, P₄ will be the limiting reagent.
Then you can apply the following rule of three: if by stoichiometry 991.16 grams of P₄ form 8 moles of P₄S₃, 20 grams of P₄ will form how many moles of P₄S₃?
moles of P₄S₃= 0.16
<u><em>The amount of P₄S₃ produced is 0.16 moles.</em></u>