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4 years ago

Calculate the mass in grams for a single molecule of carbon monoxide

Chemistry

1 answer:

Oxana [17]4 years ago

4 0

Answer:

7.307 x 10^-23

Explanation:

mass of one molecule = mr/ avogadros number

= 44/6.022 x 10^23

= 7.307x 10^-23

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$\ln(\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}[\frac{1}{T_1}-\frac{1}{T_2}]$

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1) $\Delta H_{vap}=40.68 kJ/mol=40680 J/mol$

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$T_2$ = final temperature =373 K

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Putting values in above equation, we get:

$\ln(\frac{1 atm}{P_1})=\frac{40680 J/mol}{8.314J/mol.K}[\frac{1}{363}-\frac{1}{373}]$

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$T_2$ = final temperature =383 K

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$\ln(\frac{P_2}{1 atm})=\frac{40680 J/mol}{8.314J/mol.K}[\frac{1}{373}-\frac{1}{383}]$

$P_2=1.4084 atm \approx 1.410 atm$

The vapor pressure at 383 K is 1.410 atm

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Calculate the mass in grams for a single molecule of carbon monoxide​

Calculate the mass in grams for a single molecule of carbon monoxide