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elena55 [62]
4 years ago
7

Calculate the mass in grams for a single molecule of carbon monoxide​

Chemistry
1 answer:
Oxana [17]4 years ago
4 0

Answer:

7.307 x 10^-23

Explanation:

mass of one molecule = mr/ avogadros number

= 44/6.022 x 10^23

= 7.307x 10^-23

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A beaker and a microscope
7 0
3 years ago
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To separate solid particles from a liquid, you would use:
enot [183]
Filtration

hope this helped
3 0
3 years ago
1.0 mole of KCl(aq) is added to which solution to produce a precipitate?
taurus [48]

Answer:

Ag+

Explanation:

If you imagine as if the problem were double replacement, you would pair the Cl with one of the following ions provided in the choices. As seen on Table F, Ag+ paired with Cl- produces an insoluble compound, hence the precipitate. All the other ions shown in the multiple choice section, when paired with Cl- will produce a soluble compound, as a result NOT a precipitate.

7 0
3 years ago
You are given a cube of lead that is 1.000 cm on each side. The density of lead is 11.35. How many atoms of lead are in the samp
aliya0001 [1]

<u>11.35 g</u><u> </u><u>atoms </u><u>of lead are in the sample.</u>

What does density mean?

  • The density of an area refers to the quantity of things—which may include people, animals, plants, or objects—there are in it.
  • Divide the number of objects by the area's measurement to determine density.
  • A country's population density is calculated by dividing its total population by its area, expressed in square kilometers or miles.

We can calculate the volume of the cube by cubing the side of the cube.

Volume of cube = ( 1.000 cm)³

                           = 1.000 cm³

We can now determine the amount of lead in the cube by multiplying by the density. Because we know we have a 1.000 cubic centimeter and that lead has a density of 11.35 grams per cubic centimeter, we have 11.35 grams of lead.

           =  ( 1.000 cm³) ( 11.35 \frac{g}{cm^{3} } )

         = 11.35 g

Learn more about density

brainly.com/question/15164682

#SPJ4

3 0
2 years ago
If the half-life of a radioactive substances is 590 million years and you have 40 atoms of it, how many half-lives will have pas
Nady [450]

Answer:

3

Explanation:

Applying,

2^{n'} = R/R'............... Equation 1

Where n' = number of halflives that have passed, R = Original atom of the substance, R' = atom of the substance left after decay.

From the question,

Given: R = 40 atoms, R' = 5 atoms

Substitute these values into equation 1

2^{n'} = 40/5

2^{n'} = 8

2^{n'} = 2³

Equation the base,

n' = 3

3 0
3 years ago
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