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leonid [27]
3 years ago
5

Elias observed a sample in the classroom. The sample was a liquid at room temperature. He performed a conductivity test and foun

d that it did not conduct electricity. Which classification would best fit the sample?
A) ionic
B) metal
C) nonmetal
D) salt
Chemistry
1 answer:
marusya05 [52]3 years ago
5 0

Answer:

C) nonmetal

Explanation:

Given;

The sample is in liquid state and do not conduct electricity.

We have given four types of classification.So for first,

A) Ionic

Ionic compounds are found in solid state at room temperature and it conducts electricity when dissolved in water. Hence the sample could not be ionic.

B)Metal

Metals are found in solid state at room temperature  except mercury and it conducts electricity very well. Mercury also conducts electricity.So the sample is not a metal.

C)Nonmetal

Non metals are found in solid state  except bromine which is in liquid state  at room temperature and it does not conducts electricity.

Here the property of nonmetal matches with the sample, so the sample is a nonmetal and it could be Bromine.

D)Salt

Salt is an ionic compound  found in solid state at room temperature and it conducts electricity when dissolved in water. Hence the sample could not be salt.

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How many moles of oxygen are produced when 29.2 g of water is decomposed according to H20 H2 + O2​
Katarina [22]

8.1moles

Explanation:

Given parameters:

Mass of water to be decomposed = 29.2g

Unknown:

Number of moles of oxygen.

Solution:

To solve this problem, we first write the balanced reaction equation :

               2H₂O    →     2H₂    +    O₂

Now convert the given mass of the water to number of moles;

  Number of moles of water = \frac{mass}{molar mass}

 

  Molar mass of water = 2(1) + 16 = 18g/mol

  Number of moles of water = \frac{29.2}{18}  = 16.2moles

   From the balanced reaction equation:

   2 moles of water produced 1 mole of oxygen gas;

   16.2 mole of water will produce   \frac{16.2}{2}  = 8.1moles of oxygen gas

learn more:

Number of moles brainly.com/question/1841136

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3 years ago
Why does pepsinogen become activated at ph 2?
Katena32 [7]
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5 0
2 years ago
7. A 2.0 L container had 0.40 mol of He(g) and 0.60 mol of Ar(g) at 25°C.
Finger [1]

Answer:

a) Ek Ar > Ek He

b) v Ar < v He

c) If v Ar = 431 m/s ⇒ v He = 1710.44 m/s

d) Pt = 12.218 atm

e) P He = 4.887 atm and P Ar = 7.33 atm

Explanation:

container:

∴ V = 2.0 L

∴ n He = 0.4 mol

∴ n Ar = 0.6 mol

∴ T = 25°C ≅ 298 K

a) Internal energy (U) :

∴ U = Ek + Ep = kinetic energy + potential energy

∴ Ep: the potential interaction energy is neglected, assuming ideal gas mixture

⇒ U = Ek = N(1/2mv²)= 3/2 NKT

∴ N = nNo ....number of moleculas

∴ K = 1.380 E-23 J/K....Boltzmann's constant

∴ No = 6.022 E23 molec/mol....Avogadro's number

for He:

⇒ N = (0.4)(6.022 E23) = 2.4088 E23 molec

⇒ Ek = (3/2)(2.4088 E23)(1.380 E-23 J/K)(298) = 1485.892 J

for Ar:

⇒ N = (0.6)(6.022 E23) = 3.6132 E 23 molec

⇒ Ek = (3/2)(3.6132 E23)(1.380 E-23 J/K)(298) = 2228.838 J

** Ar gas has a greater average kinetic energy

b) He:

∴ N(1/2)mv² = (3/2)NKT

⇒ mv² = 3KT

⇒ v² = 3KT/m

⇒ v = √3KT/m

∴ m He = (0.4 mol)(4.0026 g/mol) = 1.601 g He = 1.601 E-3 Kg He

⇒ v = √(3(1.380 E-23)(298)/(1.601 E-3)) = 2.776 E-9 m/s He

Ar:

∴ m Ar = (0.6)(39.948 g/mol) = 23.969 g = 0.0239 Kg Ar

⇒ v = 6.99 E-10 m/s

** v Ar < v He

c) r = V Ar / v He = (6.99 E-10 m/s)/(2.776 E-9 m/s) = 0.252

∴ If v Ar = 431 m/s

⇒ v He = v Ar/0.252 = 431 m/s / 0.252 = 1710.44 m/s

d) Pt = ntRT / V

∴ nt = 0.4 + 0.6 = 1 mol

⇒ Pt = (1mol)(0.082 atm.L/K.mol)(298 K)/(2.00 L) = 12.218 atm

e) P He = nRT/V = (0.4)(0.082)(298)/2 = 4.8872 atm

⇒ P Ar = Pt - PHe = 12.218 - 4.8872 = 7.33 atm

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3 years ago
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Answer:

Nitrogen is a chemical element that has the symbol N and atomic number 7 and atomic mass 14.00674µ.

Explanation:

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Explanation:

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