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Zepler [3.9K]
3 years ago
6

Simplify 6(x + 2) + 7. 6x + 9 6x + 15 6x + 19

Mathematics
2 answers:
miss Akunina [59]3 years ago
7 0
3rd one.

6(x + 2) is simply 6x + 12

Do 12 + 7

You will get 19.

Now put that together.

6x + 19, which is option 3

Hope this helped! :D
likoan [24]3 years ago
7 0
It’s 6x + 19
because you do 6(x + 2) u multiply the 6 times the x which is 6x and then 6 x 2 which is 12 so ur equation would be 6x + 12 + 7 so you just add 12 and 7 which is 19
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One way of solving this is using calculus: derivatives.

We have y =  \frac{x}{1 +  x^{2}}. Let's take this as a function of x.

So, 

f(x) =  \frac{x}{1 +  x^{2}}.

Now, we find it's derivative: f'(x). To do this, we use the quotient rule. The derivative [ f'(x) ] basically gives us the slope of the tangent line at a point x.

f'(x) =  \frac{1*(1 + x^{2}) - (2x *x)}{ (1 + x^{2} )^{2} } =  \frac{1 +  x^{2} - 2 x^{2} }{ (1 + x^{2} )^{2} } =  \frac{1 -  x^{2} }{ (1 + x^{2} )^{2} }

Now, we evaluate the derivative at the point x = 2 to find the slope of the tangent line at that point.

f'(2) =  \frac{1-  2^{2} }{ (1 + 2^{2} )^{2} } =  \frac{1-4}{ (5 )^{2} } =  \frac{-3}{25} = -0.12
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That's the equation.

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\dfrac{x^2-x-12}{2x}:\dfrac{x^2-2x-8}{4x^2}=\dfrac{x^2-x-12}{2x}\cdot\dfrac{4x^2}{x^2-2x-8}\\\\=\dfrac{(x+3)(x-4)}{2x}\cdot\dfrac{2x\cdot2x}{(x+2)(x-4)}=\dfrac{(x+3)}{1}\cdot\dfrac{2x}{(x+2)}\\\\=\boxed{\dfrac{2x^2+6x}{x+2}}

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