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3 years ago

Find all solutions by factoring. c? + 13c + 40 = 0

Mathematics

1 answer:

Karolina [17]3 years ago

3 0

Answer: c = -5, -8

Step-by-step explanation:

c^2 +13c+40=0

(c+5)(c+8)=40

c = -5, -8

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You want to evaluate three mutual funds using the Sharpe measure for performance evaluation. The risk-free return during the sam

riadik2000 [5.3K]

Answer:

The correct option based on the below computation of Sharpe ratio for all funds is option C,Fund C.

Step-by-step explanation:

Sharpe ratio=(Average return of the fund-risk free rate of return)/standard deviation of the fund

Risk free rate of return is 6%

Fund A:

Sharpe ratio=(24%-6%)/30%=0.6

Fund B:

Sharpe ratio=(12%-6%)/10%=0.6

Fund C:

Sharpe ratio=(22%-6%)/20%=0.8

Fund has a sharpe ratio of 0.8 ,unlike funds A& B that have a ratio of 0.6 each

In other words option C is correct

3 0

3 years ago

Factor: 2a^2-ab-6b^2

pogonyaev

Rewrite the expression as

$2a^2-4ab+3ab-6b^2$

Factor 2a from the first two terms and 3b from the last two:

$2a(a-2b)+3b(a-2b)$

Factor a-2b

$(a-2b)(2a+3b)$

5 0

3 years ago

What is the area of a rectangle with sides length of 5/12 feet and 2/3 feet

AleksandrR [38]

Answer:

The answer is 10/36 or if you want to simplify, 5/18

Step-by-step explanation:

To solve the area of a rectangle, you need to multiply the sides with each other, so 5/12 x 2/3 is 10/36 (unsimplified) . You multiply the numerators and then the denominators and simplify.

8 0

3 years ago

Determine if triangle ABC with coordinates A (0, 2), B (2, 5), and C (−1, 7) is an isosceles triangle. Use evidence to support y

kirill115 [55]

Answer:

The triangle ABC is an isosceles right triangle

Step-by-step explanation:

we have

The coordinates of triangle ABC are

A (0, 2), B (2, 5), and C (−1, 7)

we know that

An isosceles triangle has two equal sides and two equal internal angles

The formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 1

Find the distance AB

substitute in the formula

$d=\sqrt{(5-2)^{2}+(2-0)^{2}}$

$d=\sqrt{(3)^{2}+(2)^{2}}$

$dAB=\sqrt{13}\ units$

step 2

Find the distance BC

substitute in the formula

$d=\sqrt{(7-5)^{2}+(-1-2)^{2}}$

$d=\sqrt{(2)^{2}+(-3)^{2}}$

$dBC=\sqrt{13}\ units$

step 3

Find the distance AC

substitute in the formula

$d=\sqrt{(7-2)^{2}+(-1-0)^{2}}$

$d=\sqrt{(5)^{2}+(-1)^{2}}$

$dAC=\sqrt{26}\ units$

step 4

Compare the length sides

$dAB=\sqrt{13}\ units$

$dBC=\sqrt{13}\ units$

$dAC=\sqrt{26}\ units$

$dAB=dBC$

therefore

Is an isosceles triangle

Applying the Pythagoras Theorem

$(AC)^{2} =(AB)^{2}+(BC)^{2}$

substitute

$(\sqrt{26})^{2} =(\sqrt{13})^{2}+(\sqrt{13})^{2}$

$26=13+13$

$26=26$ -----> is true

therefore

Is an isosceles right triangle

8 0

3 years ago

Lim. √2x -√3x-a/√x-√a<br>x approaches a

Ludmilka [50]

Answer: $\sqrt{2}a-\sqrt{3}a-2\sqrt{a}$

Step-by-step explanation:

$\lim _{x\to \:a}\left(\sqrt{2}x-\sqrt{3}x-\frac{a}{\sqrt{x}}-\sqrt{a}\right)$

$=\sqrt{2}a-\sqrt{3}a-\frac{a}{\sqrt{a}}-\sqrt{a}$

$=\sqrt{2}a-\sqrt{3}a-2\sqrt{a}$

3 0

3 years ago