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3 years ago

32 1/2 meters to feet

Mathematics

2 answers:

Pachacha [2.7K]3 years ago

5 0

Answer:

106.6273 ft

Step-by-step explanation:

Andreas93 [3]3 years ago

3 0

Answer:

106.6273

Step-by-step explanation:

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Elenna [48]

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8 0

2 years ago

Work out the size of angle x. x 35

Naddik [55]

Answer:

145.

Step-by-step explanation:

x+35=180

x=180-35

x=145

please mark as brainliest.

5 0

3 years ago

NEED HELP ASAP PLEASE

Keith_Richards [23]

It’s the second answer
<1=58 <2=122 <3=58

7 0

3 years ago

Debbie ate 1/8 of a large brownie. Julian ate 1/2 of a small brownie, Julian says he ate more than Debbie because he said 1/2 is

Brilliant_brown [7]

Julian is correct 1/2 is fifty percent so you are half at 100

4 0

3 years ago

PLEASE HELP HELP ASAP ASAPP WILL GIVE 100 POINTS AND BRAINLEST! PLUS MY THANKS AND ADMIRATION PLEASE PLEASE!!

tatyana61 [14]

Answer:

First Picture ⇒ [B] a = -2, b = 1, and c = -5

Second Picture ⇒ First step: Identify a = 1, b = 3, c = -4

$x=\frac{-3\pm \sqrt{3^2-4\cdot \:1\cdot \left(-4\right)}}{2\cdot \:1}$

$x=\frac{-3\pm 5\sqrt{25}}{2}$

$x=\frac{-3\pm \:5}{2}$

$x=\frac{-3+5}{2},\:x=\frac{-3-5}{2\c}$

Third Picture ⇒ Missing Info

Fourth Picture ⇒ [A] $x=-\frac{5}{2},\:x=-3$

Fifth Picture ⇒ $x=\frac{5\pm\sqrt{1} }{2}$

Step-by-step explanation:

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Identify the a,b, and c-values for this equation:

y = -2x² + x -5

Quadratic Formula:

ax²+bx+c=0

−2x²+1x−5=0

a = -2, b = 1, and c = -5

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Order the steps for solving this equation using the quadratic formula.

x² + 3x - 4 = 0

Solving to see what are the steps:

First step: Identify a = 1, b = 3, c = -4

$x=\frac{-3\pm \sqrt{3^2-4\cdot \:1\cdot \left(-4\right)}}{2\cdot \:1}$

$x=\frac{-3\pm 5\sqrt{25}}{2}$

$x=\frac{-3\pm \:5}{2}$

$x_1=\frac{-3+5}{2\cdot \:1},\:x_2=\frac{-3-5}{2\cdot \:1}$

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Use the quadratic formula to find the solution set for 2x² + 15 = -11x.

Add 11x to both sides:

2x² + 15+11x = -11x+11x

Simplify

2x² + 11x+15 = 0

Now solve with quadratic formula..

$x_{1,\:2}=\frac{-11\pm \sqrt{11^2-4\cdot \:2\cdot \:15}}{2\cdot \:2}$

$x_{1,\:2}=\frac{-11\pm \:1}{2\cdot \:2}$

$x_1=\frac{-11+1}{2\cdot \:2},\:x_2=\frac{-11-1}{2\cdot \:2}$

$x=-\frac{5}{2},\:x=-3$

Hence, [A] $x=-\frac{5}{2},\:x=-3$

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Suppose you are solving a quadratic equation and this is your work so far...

x ² - 5x + 6 = 0

Thus, we have:

$x=\frac{-\left(-5\right)\pm \sqrt{\left(-5\right)^2-4\cdot \:1\cdot \:6}}{2\cdot \:1}$

$x=\frac{-\left(-5\right)\pm \:1}{2\cdot \:1}$

$x=\frac{5\pm\sqrt{1} }{2}$

$x_1=\frac{-\left(-5\right)+1}{2\cdot \:1},\:x_2=\frac{-\left(-5\right)-1}{2\cdot \:1}$

$x=3,x=2$

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Kavinsky

6 0

2 years ago