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Bad White [126]
2 years ago
12

What is the correct answer to this? Please help! Thank you so much ☺️

Mathematics
2 answers:
arsen [322]2 years ago
6 0

Answer:

second option is correct

Step-by-step explanation:

\frac{x^0y^-3}{x^2y^-1}

=x^0-2 *y-3-(-1)

=x^-2*y^-3+1

=x^-2*y-2

=\frac{1}{x^2y^2}

Paladinen [302]2 years ago
3 0

\huge\mathbb\colorbox{black}{\color{white}{AnSwEr}}

Option 2nd

=\huge\frac{1}{ { {x}^{2}  }  {y}^{2} }

\huge\pink{Law:- A⁰ = 1}

=\huge \frac{{1} \: { {y}^{ - 3} } }{ {x}^{2}  {y²}^{} }

=1/x² y-³-¹

\pink{Law:- a¹÷a²=a¹-a²}

=1/x² y²

=\huge\frac{1}{ { {x}^{2}  }  {y}^{2} }

\huge\colorbox{red}{Hope\:It\:help\:U}

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olchik [2.2K]

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aksik [14]

Answer:

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4 0
3 years ago
How do I go about solving the problem?
s344n2d4d5 [400]

Answer:

See below.

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8 0
3 years ago
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Answer:

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