Question

What is the correct answer to this? Please help! Thank you so much ☺️

Answer 1

Answer:

second option is correct

Step-by-step explanation:

$\frac{x^0y^-3}{x^2y^-1}$

=x^0-2 *y-3-(-1)

=x^-2*y^-3+1

=x^-2*y-2

=$\frac{1}{x^2y^2}$

Answer 2

$\huge\mathbb\colorbox{black}{\color{white}{AnSwEr}}$

Option 2nd

=$\huge\frac{1}{ { {x}^{2} } {y}^{2} }$

$\huge\pink{Law:- A⁰ = 1}$

=$\huge \frac{{1} \: { {y}^{ - 3} } }{ {x}^{2} {y²}^{} }$

=1/x² y-³-¹

$\pink{Law:- a¹÷a²=a¹-a²}$

=1/x² y²

=$\huge\frac{1}{ { {x}^{2} } {y}^{2} }$

$\huge\colorbox{red}{Hope\:It\:help\:U}$