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Svetradugi [14.3K]

3 years ago

11

Solve the inequality.

2 answers:

natali 33 [55]3 years ago

5 0

Answer:

C

Step-by-step explanation:

Given

9 { $\frac{x}{3}$ + 1 } ≥ 6 ( divide both sides by 9 )

$\frac{x}{3}$ + 1 ≥ $\frac{6}{9}$ , that is

$\frac{x}{3}$ + 1 ≥ $\frac{2}{3}$ ( multiply through by 3 to clear the fractions )

x + 3 ≥ 2 ( subtract 3 from both sides )

x ≥ - 1 → C

Olin [163]3 years ago

5 0

This are the steps for the answer

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1 find the area in square cm of a square whose side is

lara [203]

For question 1:

Part i)

2.6 x 2.6 = 6.76 cm squared

No unit conversions needed

Part ii)

1.2 dm = 1.2 / 1000000 = 0.0000012 cm

0.0000012 x 0.0000012 = 0.00000000000144 cm squared

Question 2:

16.5dm = 16.5/ 1000 = 0.0165 m

0.0165 x 0.0165 = 0.00027225 m squared

I hope this has helped

3 0

3 years ago

Read 2 more answers

Solve for p. <br><br> i = prt<br><br> p = i-rt<br> p = i/(rt)<br> p = (rt)/i

Debora [2.8K]

Answer:

<h2>p = (rt)/i</h2>

Step-by-step explanation:

$i=prt\to prt=i\qquad\text{divide both sides by}\ rt\neq0\\\\\dfrac{prt}{rt}=\dfrac{i}{rt}\\\\p=\dfrac{i}{rt}$

5 0

3 years ago

A screening test for a disease shows a positive result in 91% of all cases when the disease is actually present and in 7% of all

Jobisdone [24]

Answer:

0.0713 = 7.13% probability that the result is positive.

Step-by-step explanation:

Probability of a positive test:

91% of 1/650(has the disease).

7% of 1 - 1/650 = 649/650(does not have the disease). So

$p = 0.91\frac{1}{650} + 0.07\frac{649}{650} = \frac{0.91 + 0.07*649}{650} = 0.0713$

0.0713 = 7.13% probability that the result is positive.

4 0

2 years ago

Write each fraction as an expression with negative exponents.

Artemon [7]

The answer is w⁻²/v⁻².

v/w raised to the second power is (v/w)²

(v/w)² = v²/w²

Since xᵃ = 1/x⁻ᵃ, then v²/w² = 1/v⁻²w²

Since 1/xᵃ = x⁻ᵃ, then 1/v⁻²w² = w⁻²/v⁻²

8 0

2 years ago

Find p(0),p(1),p(-1) and p(2) of the 3x(x-2) <br><br>

Effectus [21]

Answer:

<u>make x→0</u>

$p(0)=(0)^{2}-3(0)+2$

→ $p(0)=0+0+2$

→ $p(0)=2$

$------$

<u>Replace x→-1</u>

$p(-1)=(-1) ^{2} -3 (-1)+2$

→ $p(-1)=1-3+2$

→ $p(-1)=0$

$----------$

<u>Now make x→2</u>

$p(2)=(2) ^{2} -3(2)+2$

→ $p(2)=4-6+2$

→ $p(2)=0$

$Answer:-2,0,0$

$-----------$

hope it helps...

have a great day!!

5 0

2 years ago