(3+3i) - (13+15i)
=3+3i-13-15i
=-10-12i
Since the slope is -2 we know that m=-2. Now use the standard form of y=mx+b and plug in the coordinates (-8,2). We know y=2, x=-8, and m=-2. Therefore we get 2=-2(-8)+b. Now solve for b and you get -14. Therefore, the equation is y=-2x-14.
Hope this helped!
If the endpoints of a diameter are (6,3) and (2,1) the midpoint is the center of the circle so:
(x,y)=((6+2)/2, (3+1)/2)=(4,2)
Now we need to find the radius....the diameter is:
d^2=(6-2)^2+(3-1)^2
d^2=16+4
d^2=20 since d=2r, r=d/2, and r^2=d^2/4 so
r^2=5
The standard form of the circle is (x-h)^2+(y-k)^2=r^2 and we know:
(h,k)=(4,2) from earlier so:
(x-4)^2+(y-2)^2=5
