Answer:
Step-by-step explanation:
Find two linear functions p(x) and q(x) such that (p (f(q(x)))) (x) = x^2 for any x is a member of R?
Let p(x)=kpx+dp and q(x)=kqx+dq than
f(q(x))=−2(kqx+dq)2+3(kqx+dq)−7=−2(kqx)2−4kqx−2d2q+3kqx+3dq−7=−2(kqx)2−kqx−2d2q+3dq−7
p(f(q(x))=−2kp(kqx)2−kpkqx−2kpd2p+3kpdq−7
(p(f(q(x)))(x)=−2kpk2qx3−kpkqx2−x(2kpd2p−3kpdq+7)
So you want:
−2kpk2q=0
and
kpkq=−1
and
2kpd2p−3kpdq+7=0
Now I amfraid this doesn’t work as −2kpk2q=0 that either kp or kq is zero but than their product can’t be anything but 0 not −1 .
Answer: there are no such linear functions.
10.
Answer: 42° and 138°
Steps: First find value of x by adding both equations and setting them equal to 180°:
3x + 12x - 30 = 180
15x - 30 = 180
15x = 210
x = 14
Next, put value of x into equations to find the angle:
3x
3(14)
42°
12x - 30
12(14) - 30
168 - 30
138°
11. Answer: 28°
Steps: Complementary angles add up to 90°, so subtract 62° from 90° to find its complementary angle.
90 - 62 = 28
12. Answer: Corresponding angles are congruent.
Answer:find the slope
Step-by-step explanation:
I don't know if you know how to find the slope if not reply back. But that's what the equation wants you to do.
