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ExtremeBDS [4]
3 years ago
8

PLEASE HELP ME WITH MY MATH WARM UP I HAVE A 71 AND IM ABOUT TO FAIL

Mathematics
1 answer:
anastassius [24]3 years ago
4 0

Answer:

Step-by-step explanation:

hi

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What is the general form of the equation of a circle with its center at (-2,1) and passing though (-4,1) ?
julsineya [31]
Equation is :( x + 2 )² + ( y - 1 )² = r²( - 4 + 2 )² + ( 1 - 1 )² = r²4 = r², than we will plug in to a formula:( x + 2 )² + ( y - 1 )² = 4x² + 4 x + 4 + y² - 2 y +1 = 4x² + y² + 4 x - 2 y + 1 = 0
the answer is : <span>x2 + y2 + 4x − 2y + 1 = 0 </span>
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3 years ago
All perfect numbers from 20 to 30
lana [24]

Answer:

There is only one perfect number between 20 to 30 which is 28.

<h3>Explanation:</h3>

The number 28 is a perfect number because its factors are 1, 2, 4, 7, 14 and 28.

7 0
2 years ago
Identify coordinate point A. <br><br> (0, 2)<br> (6, 7) <br> (1, 5)<br> (7, 3)
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Help question attached multiple choice
Rina8888 [55]

ANSWER

x =  \frac{\pi}{2} , \frac{7\pi}{6} , \frac{3\pi}{2} , \frac{11\pi}{6}

EXPLANATION

The given trigonometric equation is

\cos(x)  + 2 \cos(x)  \sin(x)  = 0

We factor cos(x) to get:

\cos(x) (1 + 2 \sin(x) ) = 0

Apply the zero product property to obtain:

\cos(x)  = 0 \: or \: 1 + 2 \sin(x)  =  0

\cos(x)  = 0 \: or \: \sin(x)  =   -  \frac{1}{2}

Using the unit circle,

\cos(x)  = 0

when

x =  \frac{\pi}{2}

and

x =  \frac{3\pi}{2}

We know

\sin(y)  =  \frac{1}{2}

when

y=  \frac{\pi}{6}

The sine function is negative in the third and fourth quadrants.

x = \pi +  \frac{\pi}{6}  =  \frac{7\pi}{6}

x = 2\pi  -   \frac{\pi}{6}  =  \frac{11\pi}{6}

Hence the solutions are:

x =  \frac{\pi}{2} , \frac{7\pi}{6} , \frac{3\pi}{2} , \frac{11\pi}{6}

6 0
3 years ago
Find the area of the circle when the circumference is 26 in
andrew11 [14]

Answer:

"None of the answers are correct."

Step-by-step explanation:

The formula for Area given the circumference is A = \frac{C^{2} }{4\pi }

\frac{26^{2} }{4\pi } = 53.79437

So none of the above are correct

3 0
3 years ago
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