Answer:(d): y=ax+b (a≠0); (d1)y=-4x+13
because of (d)⊥(d1) --> a.(-4)=-1 --> a=
(d): y=
+b. (d) pass through P(-1;-2) so we have
-2=(1/4).(-1)+b ---> b=
(d) y= 
<h3>
Answer: QR is 8 units long</h3>
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Explanation:
R is between Q and S and on segment QS, allowing us to say
QR + RS = QS
because of the segment addition postulate.
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Use substitution and solve for QR
QR + RS = QS
QR + 11 = 19
QR = 19 - 11 .... subtracting 11 from both sides
QR = 8
If you would like to find g(2), you can do this using the following steps:
g(x) = x^2 - 5x + 7
g(2) = 2<span>^2 - 5 * 2 + 7 = 4 - 10 + 7 = 1
The correct result would be d. 1.</span>
Answer:
15 2/3
Step-by-step explanation:
