The mean is 10,
The median is 10,
And there is no mode.
The mean of a set of numbers is the sum divided by the number of terms,
7+15+12+6+10=50
There are 5 numbers in the set,
50/5=10.
10 is the mean.
Arrange the data in an ascending order and the median is the middle value. If the number of values is an even number, the median will be the average of the two middle numbers,
6, 7, 10, 12, 15,
10 is in the middle so it is the median.
The mode is the element that occurs most in the data set. In this case, all elements occur only once, so there is no mode.
Just so you don’t confuse the data with the group sets,
The actual data set is 7, 15, 12, 6, and 10
This data paired with score column or group set means that,
10 people got a score of 1-10
6 people got a score of 11-20
12 people got a score of 21-30
15 people got a score of 31-40
And 7 people got a score of 41-50 :)
D. W + 118=180 is the answer for the problem
We are given a circle with a partially shaded region. First, we need to determine the area of the whole circle. To do this, we need the measurement of the radius of the circle:
Use the Pythagorean theorem to solve for the other leg of the right triangle inside the circle:
5^2 = 3^2 + x^2
x = 4
The radius is 4 + 1 cm = 5 cm
So the area of the circle is A = pi*r^2
A = 3.14 * (5)^2
A = 25pi cm^2
To solve for the area of the shaded region:
Ashaded = Acircle - Atriangles
we need to solve for the area of the triangles:
A = 1/2 *b*h
A = 1/2 *6 * 5
A = 15 cm^2
Atriangles = 2 * 15
Atriangles = 30 cm^2
Ashaded = 25pi - 30
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7x^-8 * 6x^3 = (7 x 6)x^(-8 + 3) = 42x^-5 = 42/x^5
The poverty level cutoff in 1987 to the nearest dollar was $10787.
<h3>
How to find a midpoint?</h3>
The midpoint as the point that divides the line segment exactly in half having two equal segments. Therefore, the midpoint presents the same distance between the endpoints for the line segment. The midpoint formula is: .
For solving this exercise, first you need plot the points in a chart. See the image.
Your question asks to approximate the poverty level cutoff in 1987 to the nearest dollar using the midpoint formula. Note that the year 1987 is between 1980 and 1990, thus you should apply the midpoint formula from data for this year (1987).
The answer for your question will be the value that you calculated for the y-coordinate. Then, the poverty level cutoff in 1987 to the nearest dollar was $10787.
Read more about the midpoint segment here:
brainly.com/question/11408596