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weqwewe [10]
3 years ago
7

A b or c or d??? Who did it

Mathematics
2 answers:
AVprozaik [17]3 years ago
5 0

Answer:

is C maybe

Step-by-step explanation:

don't really know just picked

ruslelena [56]3 years ago
4 0

TAnswer: it should be A

Step-by-step explanation:

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Evaluate 3x² - 4xy + 2y² - 1 for x = - 3 and y = 5
zhannawk [14.2K]

Answer:

3x^{2} - 4xy + 2y { }^{2} - 1  \\ 3 \times ( - 3) { }^{2}  - 4 \times ( - 3)  \times 5 + 2 \times 5 {}^{2} - 1 \\ (3 \times 9) - ( - 60) + 50 - 1 \\ 27 + 60 + 50 - 1 \\ 165

8 0
1 year ago
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Please please please help and solve this with steps, much help needed thank you :) 20 points for this!
leonid [27]

Answer:

y=\sqrt{\frac{x^4-6x^2+12x+c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+c_1}{2}}

(Please vote me Brainliest if this helped!)

Step-by-step explanation:

\frac{dy}{dx}y=x^3+2x-5x+3

\mathrm{First\:order\:separable\:Ordinary\:Differential\:Equation}

  • \mathrm{A\:first\:order\:separable\:ODE\:has\:the\:form\:of}\:N\left(y\right)\cdot y'=M\left(x\right)

1. \mathrm{Substitute\quad }\frac{dy}{dx}\mathrm{\:with\:}y'\:

y'\:y=x^3+2x-5x+3

2. \mathrm{Rewrite\:in\:the\:form\:of\:a\:first\:order\:separable\:ODE}

yy'\:=x^3-3x+3

  • N\left(y\right)\cdot y'\:=M\left(x\right)
  • N\left(y\right)=y,\:\quad M\left(x\right)=x^3-3x+3

3. \mathrm{Solve\:}\:yy'\:=x^3-3x+3:\quad \frac{y^2}{2}=\frac{x^4}{4}-\frac{3x^2}{2}+3x+c_1

4. \mathrm{Isolate}\:y:\quad y=\sqrt{\frac{x^4-6x^2+12x+4c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+4c_1}{2}}

5. \mathrm{Simplify}

y=\sqrt{\frac{x^4-6x^2+12x+c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+c_1}{2}}

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3 years ago
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3b 2a=5a−6 solve the equation for a in terms of <br> b.
oee [108]
Is it 3b-2a=5a-6
or
3b+2a=5a-6

you are missing the sign of 2a
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3 years ago
Jose constructed Triangle DCE, where m
lord [1]

Answer:

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Step-by-step explanation:

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Determine which of the ordered pairs are a part of the solution set of y + 3 &lt; 2x (0, –4)
lorasvet [3.4K]

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y+3<2x

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