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2 years ago

ANSWER PLSNO LINKS AT ALL

Mathematics

1 answer:

lianna [129]2 years ago

4 0

Answer:

David (1), Billy (2), Allen (5), Conner (7).

Step-by-step explanation:

Use M.A.D to find variability. Basically the higher the M.A.D, the greater the variability. And I don't know for sure, so if wrong tell me.

You might be interested in

How to find the area of a rectangular prism?

patriot [66]

(base area)*h
oibgrawjk gr/

8 0

2 years ago

How would I find the range btw im only allowed a Ti-84 calculator So pls tell me how to solve this without using any stepbystep

jek_recluse [69]

It would be c because when you multiply each number by r you can see the number

7 0

2 years ago

Two triangles can be formed with the given information. Use the Law of Sines to solve the triangles. A = 56°, a = 12, b = 14

Eva8 [605]

We know that
case 1)
Applying the law of sines
a/Sin A=b/Sin B
A=56°
a=12
b=14
so
a*Sin B=b*Sin A----> Sin B=b*Sin A/a---> Sin B=14*Sin 56°/12
Sin B=0.9672
B=arc sin (0.9672)------> B=75.29°-----> B=75.3°

find angle C
A+B+C=180°-----> C=180-(A+B)----> C=180-(56+75.3)----> C=48.7°

find c
a/Sin A=c/Sin C----> c=a*Sin C/Sin A----> c=12*Sin 48.7°/Sin 56°)
c=10.87-----> c=10.9

the answer Part 1)
the dimensions of the triangle N 1
are
a=12 A=56°
b=14 B=75.3°
c=10.9 C=48.7°

case 2)
A=56°
a=12
b=14
B=180-75.3----> B=104.7°

find angle C
A+B+C=180°-----> C=180-(A+B)----> C=180-(56+104.7)----> C=19.3°

find c
a/Sin A=c/Sin C----> c=a*Sin C/Sin A----> c=12*Sin 19.3°/Sin 56°)
c=4.78-----> c=4.8

the answer Part 2)
the dimensions of the triangle N 2
are
a=12 A=56°
b=14 B=104.7°
c=4.8 C=19.3°

3 0

3 years ago

Can someone help me with this answer I’m on a test and it’s almost due

Brrunno [24]

16.5 / p = 11 / 18

p = 16.5 × 18 / 11

p = ( 16.5 / 11 ) × 18

p = 1.5 × 18

p = 27

6 0

3 years ago

Find the Area of the figure below, composed of an isoceles trapezoid and one

MAVERICK [17]

Answer:

the total area is 15.6 square units

Step-by-step explanation:

hello,

you can find the total area dividing the shape into two known shapes

total area= area of the trapezoid +area of the semicircle

then

step one

find the area of the isosceles trapezoid using

$A=\frac{a+b}{2}*h$

where

a is the smaller base

b is the bigger base

h is theheight

A is the area

let

a=2

b=5

h=4

put the values into the equation

$A=\frac{a+b}{2}*h\\A=\frac{5+2}{2}*4\\A=3.5*4\\A=14$

Step two

find the area of the semicircle

the area of a circle is given by

$A_{c}=\pi \frac{d^{2}}{4}\\$

but, we need the area of half circle, we need divide this by 2

$A_{semic}=\frac{ \pi \frac{d^{2}}{4}}{2}\\A_{semic}= \pi \frac{d^{2}}{8}$

now the diameter of the semicircle is 2, put this value into the equation

$A_{semic}= \pi \frac{2^{2}}{8}\\\\A_{semic}= \pi \frac{1}{2}\\ A_{semic}=\frac{\pi }{2}\\$

find the total area

total area= area of the trapezoid +area of the semicircle

$total\ area= 14+\frac{\pi }{2} \\total\ area=15.6$

so, the total area is 15.6 square units

Have a good day.

5 0

3 years ago

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