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2 years ago

1. f(x) = x; h(x) = 4x - 2

Mathematics

1 answer:

ExtremeBDS [4]2 years ago

6 0

Answer:

=4x-2

Step-by-step explanation:

f=x, h=4x-2, f(x) *h(x): 4x-2

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Three sets Venn diagram

Anon25 [30]

Answer:

I hope this helps a little bit

8 0

2 years ago

The number of measles cases increased 13.6 % to 57 cases this year, what was the number of cases prior to the increase? (Express

ELEN [110]

Answer:

The number of cases prior to the increase is 50.

Step-by-step explanation:

It is given that the number of measles cases increased by 13.6% and the number of cases after increase is 57.

We need to find the number of cases prior to the increase.

Let x be the number of cases prior to the increase.

x + 13.6% of x = 57

$x+x\times \frac{13.6}{100}=57$

$x+0.136x=57$

$1.136x=57$

Divide both the sides by 1.136.

$\frac{1.136x}{1.136}=\frac{57}{1.136}$

$x=50.176$

$x\approx 50$

Therefore the number of cases prior to the increase is 50.

7 0

3 years ago

Divide 114÷7 explain the anwser

bezimeni [28]

To get the answer you must see how many times 7 can go in 114

5 0

3 years ago

Read 2 more answers

Would someone do number 10 and 12

Sliva [168]

Answer:

they would divide it

Step-by-step explanation:

because that what some people would do

5 0

3 years ago

A container contains 12 diesel engines. The company chooses 5 engines at random, and will not ship the container if any of the

Rufina [12.5K]

Answer: $\frac{^{10}C_5}{^{12}C_5}$

Step-by-step explanation:

Given a total of 12 diesel engines

out of which 2 are defective

Company have to choose 5 good engines to ship.

Therefore no of ways in good engines are selected is $^{10}C_5$

no of ways in which any 5 engines are selected from a total of 12 engines is

$^{12}C_5$

Therefore the required probability = $\frac{^{10}C_5}{^{12}C_5}$

= $\frac{7}{22}$ =0.318

3 0

2 years ago