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Ilya [14]
3 years ago
10

Write the equation of the parabola in vertex form vertex (1,2), point (2,-3)

Mathematics
1 answer:
Andrew [12]3 years ago
4 0

Answer:

Step-by-step explanation:

Find the parabola through  ( 2 , − 3 )  with vertex  ( 1 , 2 ) .

Standard Form:  y = 5 x ² − 20 x + 17

Vertex Form:  y = 5 ( x − 2 ) ²− 3

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What is the product?
ZanzabumX [31]
To get the answer to this equation you first cancel out the 6! ;)

(x^2-1)(6x-1) / (x+1)

Then rewrite x^2-1 in the form a^2 + b^2, where a=x and b=1

(x^2-1^2)(6x-1) / (x+1)

Then use the difference of squares!

(x+1)(x-1)(6x-1) / (x+1)

LASTLY cancel "x+1" !

so ur answer is (x-1) (6x-1)

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3 divided by 4 in fraction form
Kitty [74]
Answer: 3/4 is the answer
3 0
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A spherical balloon has a circumference of 23 cm. What is the approximate surface area of the balloon to the nearest square cent
Bad White [126]
168cm2
Let r cm be the radius of the balloon, then 
<span>2pi(r)=23=>r=23/(2pi) </span>
<span>The surface area= </span>
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Answer:

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6 0
3 years ago
Sum and Product of zeroes of the quadratic polynomial 16s² - 16s + 4 respectively is:Sum and Product of zeroes of the quadratic
andrew-mc [135]

Answer:

The sum and product of zeroes are 1 and 1/4, respectively.

Step-by-step explanation:

To determine the zeroes of the quadratic polynomial, let equalize the polynomial to zero and solve in consequence:

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By the General Quadratic Formula:

s_{1,2} = \frac{16\pm \sqrt{(-16)^{2}-4\cdot (16)\cdot (4)}}{2\cdot (16)}

s_{1,2} = \frac{1}{2}

Which means that zeroes are s_{1}=s_{2}=\frac{1}{2}.

The sum and product of zeroes are, respectively:

s_{1}+s_{2} =\frac{1}{2}+\frac{1}{2}

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The sum and product of zeroes are 1 and 1/4, respectively.

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