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Lostsunrise [7]

3 years ago

6

The high temperature in a city one day was 22.8°C. The low temperature was -2.4°C. What was the temperature range (difference) i

n the city that day?

1 answer:

faust18 [17]3 years ago

4 0

Answer:

25.2°C

Step-by-step explanation:

Find the difference: 22.8-(-2.4)=22.8+2.4=25.2

Therefore, the temperature range in the city that day was 25.2°C

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Jon caught four fish that weighed a total of 252 pounds. The kingfish weighed twice as much as the amberjack and the white marli

Allushta [10]

Answer:

amberjack, 21 lbs
kingfish, 42 lbs
white marlin, 84 lbs
tarpon, 105 lbs

Step-by-step explanation:

Let k, a, m, t represent the weights of the kingfish, amberjack, marlin, and tarpon, respectively. The problem statement tells us ...

k = 2a
m = 2k
t = 5a
k + a + m + t = 252

Using substitution, we can rewrite the last equation as ...

... (2a) + (a) + 2(2a) + (5a) = 252

... 12a = 252 . . . . . collect terms

... a = 21 . . . . . . . . .divide by 12

Then k = 2a = 42; m = 2k = 84; t = 5a = 105.

8 0

2 years ago

A line with a slope of 9/7 passes through the point (7, 14).What is its equation in slope -intercept form?

ad-work [718]

Answer:

y=9/7x+5

Explanation:

We have the slope, and a point that is not an intercept. We can use Desmos graphing calculator to test y-intercepts.

6 0

2 years ago

Tara is using matrix multiplication to find image points of a translation. She is translating the image 2 units left and 4 units

Ahat [919]

Assuming that this is just on a 2-D coordinate plane, we must convert the expressions on to a 3-D plane since translation cannot be done on a 2-D plane. This is done by adding a dummy coordinate that does not change. Let us use "1" for this case.

Matrix:
| 0 0 -2 |(x) = (x - 2)
<span>| 0 0 4 |(y) = (y + 4)
</span><span>| 0 0 1 |(1) = 1</span>

7 0

3 years ago

A pile of cards has 3 black cards and 5 red cards. Alex picks 6 cards out of the pile, without replacement. Which of the followi

scoray [572]

Answer:

)Alex picks more red cards than black cards,

Step-by-step explanation:

4 0

2 years ago

"A cable TV company wants to estimate the percentage of cable boxes in use during an evening hour. An approximation is 20 percen

Marizza181 [45]

Answer:

The company should take a sample of 148 boxes.

Step-by-step explanation:

Hello!

The cable TV company whats to know what sample size to take to estimate the proportion/percentage of cable boxes in use during an evening hour.

They estimated a "pilot" proportion of p'=0.20

And using a 90% confidence level the CI should have a margin of error of 2% (0.02).

The CI for the population proportion is made using an approximation of the standard normal distribution, and its structure is "point estimation" ± "margin of error"

[p' ± $Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }$ ]

Where

p' is the sample proportion/point estimator of the population proportion

$Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }$ is the margin of error (d) of the confidence interval.

$Z_{1-\alpha /2} = Z_{1-0.05} = Z_{0.95}= 1.648$

So

$d= Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }$

$d *Z_{1-\alpha /2}= \sqrt{\frac{p'(1-p')}{n} }$

$(d*Z_{1-\alpha /2})^2= \frac{p'(1-p')}{n}$

$n*(d*Z_{1-\alpha /2})^2= p'(1-p')$

$n= \frac{p'(1-p')}{(d*Z_{1-\alpha /2})^2}$

$n= \frac{0.2(1-0.2)}{(0.02*1.648)^2}$

n= 147.28 ≅ 148 boxes.

I hope it helps!

3 0

3 years ago