Answer: z = 
Step-by-step explanation:
To find <em>z</em>, you must set up a proportion to solve.
To find the altitude of a special right triangle, the formula is:
You can use <em>5</em> as <em>a</em> and <em>2</em> as <em>b</em> to complete the proportion:
Next, to solve:
<u>Step 1</u>: Cross-multiply.
(5)*(2) = z*z
10 = z²
<u>Step 2</u>: Take square root.
10 = z²
√10 = z
I hope this helps!
Answer:
0.69
Step-by-step explanation:
Answer:
Using a rule is direct and not time wasting, which is not the case for listing functions
Are the problems separated?
Answer:
A. x = 58°
B. x = 10m
C. a = 44°
All approximated to nearest whole number.
Step-by-step explanation:
All triangles given are right angled triangles. Therefore, we would apply the trigonometry functions to solve for each missing side and angle.
Recall: SOHCAHTOA
a. Adjacent = 4.8cm,
Hypotenuse = 9cm
Angle to find =x°
Thus, we would apply the following formula:
Cos θ = Adjacent/Hypotenuse
Cos θ = 4.8/9 = 0.5333
θ = Cos-¹(0.5333) = 57.77
x ≈ 58° (to nearest whole number)
b. Opposite side = x
Hypothenuse = 40 m
Included angle = 14°
We would use:
Sine θ = opposite/hypothenuse
Sin (14) = x/40
Multiply both sides by 40
40*sin(14) = x
40*0.2419 = x
x = 9.676 = 10 m (to nearest whole number)
c. Opposite = 87mm
Adjacent = 91mm
θ = a°
We would use:
Tan θ = opposite/adjacent
Tan θ = 87/91
Tan θ = 0.9560
θ = tan-¹(0.9560)
θ = a = 43.71
a ≈ 44° (to nearest whole number)
