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Lostsunrise [7]
3 years ago
12

13/17% of a quantity is equal to what fraction of the quality

Mathematics
2 answers:
Nookie1986 [14]3 years ago
8 0

Answer:

13/1700

Step-by-step explanation:

so you do 13/17 x 1/100 which is 13/1700 please mark brainliest

miskamm [114]3 years ago
6 0

Answer:

Step-by-step explanation:

13/17% of a quantity is equal to (13/17) of that quantity, or approximately 0.76.

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The difference of the square of a number and 40 is equal to 3 times that number. Find the positive solution.
Wewaii [24]

Answer: The answer is 8.

Step-by-step explanation: The first step is to convert the expression into figures. We shall call the unknown number Y. So if we are told “the square of a number,” that means Y squared, or better still, Y^2. Further we are told “the difference between the square of a number and 40” and that can be written as;

Y^2 - 40.

Next we are told that this expression is equal to 3 times that number (that is 3Y). That can now be written out as follows,

Y^2 - 40 = 3Y

If we move all expressions to one side of the equation, what we would have is,

Y^2 - 3Y -40 = 0

(Remember that when a positive value crosses to the other side of an equation it becomes negative and vice versa)

We now have a quadratic equation

Y^2 -3Y - 40 = 0

By factorizing we now have

(Y -8) (Y + 5) = 0

Therefore Y - 8 = 0 or

Y + 5 = 0

Hence, Y = 8 or Y = -5

Since we are asked to calculate the positive solution, Y = 8

5 0
4 years ago
Help pleasee<br> Qn is attached belowww <br> PLEASE HELPP
Simora [160]

Answer:

QR = 65.4 m

Step-by-step explanation:

a. Apply Law of Cosines to find QR:

p² = q² + r² - 2qr × Cos P

p = QR = ?

q = PR = 150 m

r = PQ = 120 m

P = 25°

Plug in the values

p² = 150² + 120² - (2)(150)(120) × Cos(25°)

p² = 22,500 + 14,400 - 36,000 × 0.9063

p² = 36,900 - 32,626.8

p² = 4,273.2

p = √4,273.2

p ≈ 65.4 m (nearest tenth)

QR = 65.4 m

7 0
3 years ago
Write the equation....
BaLLatris [955]
1-0/-1-0 = -1
Y- 0 = -(x-0)
Y=-x
Y - 1 = -(x+1)
Y-1= -x-1
Y = -x
5 0
3 years ago
For the given polynomials find the sum of the squares of the roots. P(x)=x^3-x^2-18x+k
slega [8]

\text{Given that,}\\\\P(x) = x^3 -x^2 -18x+k\\\\\text{If the roots are}~ \alpha, ~ \beta,~\text{and}~ \gamma, ~ \text{then},\\\\\alpha +\beta+\gamma= -\dfrac{(-1)}1 = 1\\\\\alpha \beta +\beta \gamma + \gamma \alpha= -\dfrac{18}1 = -18\\ \\\text{Now, sum of the  squares of the roots,}\\\\\alpha^2 + \beta^2 + \gamma^2 = ( \alpha + \beta + \gamma)^2 -2(\alpha \beta + \gamma \beta + \gamma \alpha)\\ \\~~~~~~~~~~~~~~~~~~=1^2 - 2(-18)\\\\~~~~~~~~~~~~~~~~~~=1+36\\\\~~~~~~~~~~~~~~~~~~=37

6 0
2 years ago
Find the quotient.<br>1. (a a<br>8.<br>2<br>​
kirill [66]

Answer:

what was it what aa or 2 8 kesa question

4 0
2 years ago
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